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Find the sum of the first (54) natural numbers.

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Answer and explanation

Correct answer: 1485

The sum of the first \(n\) natural numbers is \(S_n=\frac{n(n+1)}{2}\). Therefore, \(S_{54}=\frac{54\times55}{2}=27\times55=1485\). Hence, 1485 is the correct answer. A value such as 1475 may result from a small multiplication or addition error. Exam tip: for the sum of consecutive numbers from 1 to \(n\), use \(\frac{n(n+1)}{2}\).

Related tags

Sequences And ProgressionsSum Of Natural NumbersArithmetic SeriesFormula ApplicationClass 9 Mathematics

Frequently asked questions

What is the correct answer to this question?

1485

Why is this the correct answer?

The sum of the first \(n\) natural numbers is \(S_n=\frac{n(n+1)}{2}\). Therefore, \(S_{54}=\frac{54\times55}{2}=27\times55=1485\). Hence, 1485 is the correct answer. A value such as 1475 may result from a small multiplication or addition error. Exam tip: for the sum of consecutive numbers from 1 to \(n\), use \(\frac{n(n+1)}{2}\).

Which subject and chapter does this question cover?

This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Sum of first n natural numbers.

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