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Find (\frac{9^{-1}}{3^{-4}}).(\frac{9^{-1}}{3^{-4}}) का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: 99
Since \(9=3^2\), we have \(9^{-1}=3^{-2}\). Using the division law for powers with the same base, \(a^m\div a^n=a^{m-n}\), we get \(3^{-2}\div3^{-4}=3^{-2-(-4)}=3^2=9\). Therefore, option A is correct. In exams, take special care that subtracting \(-4\) becomes addition of 4.क्योंकि \(9=3^2\), इसलिए \(9^{-1}=3^{-2}\)। अब समान आधार वाली घातों के भाग का नियम \(a^m\div a^n=a^{m-n}\) लगाने पर \(3^{-2}\div3^{-4}=3^{-2-(-4)}=3^2=9\)। अतः सही विकल्प A है। परीक्षा में ऋणात्मक घातों का घटाव करते समय \(-(-4)=+4\) अवश्य ध्यान रखें।
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