Choose the value of the sum of the first (21) natural numbers.
Answer and explanation
Correct answer: 231
The sum of the first \(n\) natural numbers is \(\frac{n(n+1)}{2}\). Substituting \(n=21\), we get \(\frac{21\times22}{2}=21\times11=231\). Hence, option B is correct. \(210\) is the sum from \(1\) to \(20\), so it is a close but incorrect choice. Exam tip: identify \(n\) and \(n+1\) carefully before applying the formula.
Frequently asked questions
What is the correct answer to this question?
231
Why is this the correct answer?
The sum of the first \(n\) natural numbers is \(\frac{n(n+1)}{2}\). Substituting \(n=21\), we get \(\frac{21\times22}{2}=21\times11=231\). Hence, option B is correct. \(210\) is the sum from \(1\) to \(20\), so it is a close but incorrect choice. Exam tip: identify \(n\) and \(n+1\) carefully before applying the formula.
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Sum of first n natural numbers.
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