किसी पौधे की ऊंचाई (t=3) पर (34) सेमी और (t=9) पर (82) सेमी है। यदि वृद्धि रेखीय है तो सही मॉडल क्या होगा?

A plant's height is (34) cm at (t=3) and (82) cm at (t=9). If the growth is linear then what is the correct model?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. (H(t)=10+8t)

Step 1

Concept

The rate is \(\frac{82-34}{9-3}=8\). From (34=a+8(3)), (a=10).

Step 2

Why this answer is correct

The correct answer is A. (H(t)=10+8t). The rate is \(\frac{82-34}{9-3}=8\). From (34=a+8(3)), (a=10).

Step 3

Exam Tip

दर \(\frac{82-34}{9-3}=8\) है। (34=a+8(3)) से (a=10) मिलता है।

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किसी पौधे की ऊंचाई (t=3) पर (34) सेमी और (t=9) पर (82) सेमी है। यदि वृद्धि रेखीय है तो सही मॉडल क्या होगा? / A plant's height is (34) cm at (t=3) and (82) cm at (t=9). If the growth is linear then what is the correct model?

Correct Answer: A. (H(t)=10+8t). Explanation: दर \(\frac{82-34}{9-3}=8\) है। (34=a+8(3)) से (a=10) मिलता है। / The rate is \(\frac{82-34}{9-3}=8\). From (34=a+8(3)), (a=10).

Which concept should I revise for this Mathematics MCQ?

The rate is \(\frac{82-34}{9-3}=8\). From (34=a+8(3)), (a=10).

What exam hint can help solve this Mathematics question?

दर \(\frac{82-34}{9-3}=8\) है। (34=a+8(3)) से (a=10) मिलता है।