किसी पौधे की ऊंचाई (t=2) पर (31) सेमी और (t=7) पर (76) सेमी है। यदि वृद्धि रेखीय है तो सही मॉडल क्या होगा?

A plant's height is (31) cm at (t=2) and (76) cm at (t=7). If the growth is linear then what is the correct model?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. (H(t)=13+9t)

Step 1

Concept

The rate is \(\frac{76-31}{7-2}=9\). From (31=a+9(2)), (a=13).

Step 2

Why this answer is correct

The correct answer is A. (H(t)=13+9t). The rate is \(\frac{76-31}{7-2}=9\). From (31=a+9(2)), (a=13).

Step 3

Exam Tip

दर \(\frac{76-31}{7-2}=9\) है। (31=a+9(2)) से (a=13) मिलता है।

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किसी पौधे की ऊंचाई (t=2) पर (31) सेमी और (t=7) पर (76) सेमी है। यदि वृद्धि रेखीय है तो सही मॉडल क्या होगा? / A plant's height is (31) cm at (t=2) and (76) cm at (t=7). If the growth is linear then what is the correct model?

Correct Answer: A. (H(t)=13+9t). Explanation: दर \(\frac{76-31}{7-2}=9\) है। (31=a+9(2)) से (a=13) मिलता है। / The rate is \(\frac{76-31}{7-2}=9\). From (31=a+9(2)), (a=13).

Which concept should I revise for this Mathematics MCQ?

The rate is \(\frac{76-31}{7-2}=9\). From (31=a+9(2)), (a=13).

What exam hint can help solve this Mathematics question?

दर \(\frac{76-31}{7-2}=9\) है। (31=a+9(2)) से (a=13) मिलता है।