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A battery remains (B(h)=100-10h) percent. How much battery will remain at (h=6)?

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Answer and explanation

Correct answer: 40%

The given function is \(B(h)=100-10h\). Substituting \(h=6\), \(B(6)=100-10(6)=100-60=40\). Therefore, 40% battery remains. The option 50% is incorrect because the decrease in 6 hours is \(10\times6=60\) percentage points, not 50. Exam tip: In linear-decay questions, substitute the given value of \(h\) first, then multiply and subtract.

Related tags

Linear DecayLinear FunctionSubstitutionBattery PercentagePolynomials

Frequently asked questions

What is the correct answer to this question?

40%

Why is this the correct answer?

The given function is \(B(h)=100-10h\). Substituting \(h=6\), \(B(6)=100-10(6)=100-60=40\). Therefore, 40% battery remains. The option 50% is incorrect because the decrease in 6 hours is \(10\times6=60\) percentage points, not 50. Exam tip: In linear-decay questions, substitute the given value of \(h\) first, then multiply and subtract.

Which subject and chapter does this question cover?

This is a Class 9 Mathematics question. Chapter: Introduction to Polynomials. Topic: Linear growth and decay.

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