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If (S_n-S_{n-2}=199), what will be the value of (S_n)?

Answer and explanation

Correct answer: 5050

Let \(S_n\) be the sum of the first \(n\) natural numbers. In \(S_n-S_{n-2}\), only the last two terms, \((n-1)\) and \(n\), remain. Hence, \(2n-1=199\), giving \(n=100\). Therefore, \(S_{100}=\frac{100\times101}{2}=5050\). Option 4950 is the sum of the first 99 natural numbers, so it is not correct. Exam tip: interpret \(S_n-S_{n-2}\) directly as the sum of the last two terms.

Related tags

Sequences And ProgressionsSum Of Natural NumbersPartial SumsAlgebraic ReasoningClass 9 MathematicsSum Of First N Natural NumbersMathematicsClass 9 Mcq

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