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If (S_n-S_{90}=5775), what will be the value of (n)?

Answer and explanation

Correct answer: 140

The sum of the first 90 natural numbers is \(S_{90}=\frac{90\times91}{2}=4095\). Hence, \(S_n=5775+4095=9870\). Using \(\frac{n(n+1)}{2}=9870\), we get \(n(n+1)=19740=140\times141\); therefore, \(n=140\). For instance, if \(n=135\), the sum is \(\frac{135\times136}{2}=9180\), not the required \(9870\). Exam tip: In such questions, first add the known \(S_k\) to find \(S_n\).

Related tags

Sequences And ProgressionsSum Of Natural NumbersArithmetic SeriesQuadratic EquationClass 9 MathematicsSum Of First N Natural NumbersMathematicsClass 9 Mcq

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