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What is the value of (S_{78}-S_{52}+S_{26}) for sums of the first (52), first (78), and first (26) natural numbers?

Answer and explanation

Correct answer: 2054

The sum of the first \(n\) natural numbers is \(S_n=\frac{n(n+1)}{2}\). Thus, \(S_{78}=\frac{78\times79}{2}=3081\), \(S_{52}=\frac{52\times53}{2}=1378\), and \(S_{26}=\frac{26\times27}{2}=351\). Hence, \(S_{78}-S_{52}+S_{26}=3081-1378+351=2054\). Exam tip: evaluate each \(S_n\) separately, then apply the signs in the expression carefully.

Related tags

Sequences And ProgressionsSum Of Natural NumbersArithmetic SeriesFormula ApplicationNumber SeriesSum Of First N Natural NumbersMathematicsClass 9 Mcq

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