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If (S_{2k+1}=1770), what will be the value of (k)?

Answer and explanation

Correct answer: 29

The sum of the first n natural numbers is \(S_n=\frac{n(n+1)}{2}\). Here, \(\frac{n(n+1)}{2}=1770\) gives \(n=59\), since \(\frac{59\times60}{2}=1770\). Therefore, \(2k+1=59\), so \(2k=58\) and \(k=29\). Option 30 may result from incorrectly taking the index as 60 instead of 59. Exam tip: first find n from \(S_n\), then equate the given index \(2k+1\) to n.

Related tags

MathematicsSequences And ProgressionsSum Of Natural NumbersAlgebraSeriesSum Of First N Natural NumbersClass 9 Mcq

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