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If (S_a=2485) and (S_b=3570), what will be the value of (b-a)?

Answer and explanation

Correct answer: \(14\)

The sum of the first \(n\) natural numbers is \(S_n=\frac{n(n+1)}{2}\). From \(\frac{a(a+1)}{2}=2485\), we get \(a=70\), since \(\frac{70\times71}{2}=2485\). Similarly, \(\frac{b(b+1)}{2}=3570\) gives \(b=84\), since \(\frac{84\times85}{2}=3570\). Therefore, \(b-a=84-70=14\). A close distractor such as \(12\) may result from incorrectly identifying the indices. Exam tip: first express each given sum using \(\frac{n(n+1)}{2}\), then determine \(n\).

Related tags

MathematicsSequences And ProgressionsNatural NumbersSum Of Natural NumbersTriangular NumbersSum Of First N Natural NumbersClass 9 Mcq

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