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In a triangular parking arrangement, the (1)st row has (2) vehicles, the (2)nd has (4) vehicles, and the (40)th has (80) vehicles. How many vehicles are there in total?

Answer and explanation

Correct answer: 1640

The numbers of vehicles in the rows are 2, 4, 6, ..., 80, so the number in each row is twice its row number. Hence the total is \(2(1+2+3+\cdots+40)\). Since \(1+2+\cdots+40=\frac{40\times41}{2}=820\), the total is \(2\times820=1640\) vehicles. The value 1600 may result from using \(40\times40\), but that is not the correct sum of this arithmetic progression. Exam tip: identify the first term, last term and number of terms, then use \(S_n=\frac{n}{2}(a+l)\).

Related tags

MathematicsArithmetic ProgressionSequence SumsNatural NumbersTriangular ArrangementSum Of First N Natural NumbersSequences And ProgressionsClass 9 Mcq

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