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If (S_{2p}=820), what is the value of (p)?

Answer and explanation

Correct answer: 20

The sum of the first \(n\) natural numbers is \(S_n=\frac{n(n+1)}{2}\). Here, \(S_{2p}=820\), so \(\frac{2p(2p+1)}{2}=820\). Since \(\frac{40\times41}{2}=820\), we get \(2p=40\), hence \(p=20\). If \(p=19\), the index would be \(38\), whose sum is not 820. Exam tip: When a sum is given, equate it to \(n(n+1)/2\) and find the index \(n\) first.

Related tags

MathematicsSequences And ProgressionsNatural NumbersSum Of Natural NumbersSeries FormulasSum Of First N Natural NumbersClass 9 Mcq

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