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How much greater is the sum of the first (40) natural numbers than the sum of the first (20) natural numbers?

Answer and explanation

Correct answer: 610

The sum of the first 40 natural numbers is \(S_{40}=\frac{40\times41}{2}=820\), and the sum of the first 20 natural numbers is \(S_{20}=\frac{20\times21}{2}=210\). Therefore, the required difference is \(820-210=610\), so option C is correct. Getting 600 usually results from an arithmetic error in multiplication or subtraction. Exam tip: In such questions, use \(S_n=\frac{n(n+1)}{2}\) and subtract the two sums.

Related tags

MathematicsSequences And ProgressionsNatural NumbersSum Of N Natural NumbersArithmetic SeriesSum Of First N Natural NumbersClass 9 Mcq

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