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What remains when (1+2+\cdots+50) is subtracted from (1+2+\cdots+80)?

Answer and explanation

Correct answer: 1965

The sum of the first 80 natural numbers is \(\frac{80\times81}{2}=3240\), and the sum of the first 50 natural numbers is \(\frac{50\times51}{2}=1275\). Therefore, the required difference is \(3240-1275=1965\). Equivalently, it is the sum of the integers from 51 to 80. Exam tip: use \(n(n+1)/2\) carefully for both sums to avoid a close error such as 1975.

Related tags

Sequences And ProgressionsNatural NumbersSum FormulaArithmetic SeriesDifference Of SumsSum Of First N Natural NumbersMathematicsClass 9 Mcq

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