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What is the sum of the natural numbers from 91 to 100?

Answer and explanation

Correct answer: 955

Direct answer: option C, 955. The numbers 91 through 100 form ten consecutive terms. Using the sum formula Sₙ = n(n + 1)/2, the required partial sum is S₁₀₀ − S₉₀. Now S₁₀₀ = 100 × 101/2 = 5050 and S₉₀ = 90 × 91/2 = 4095. Therefore, the required sum is 5050 − 4095 = 955. A second check is useful: the first and last numbers have average (91 + 100)/2 = 95.5, and there are 10 numbers, so the sum is 10 × 95.5 = 955. Option A, 935, is too small and may come from a subtraction error. Option B, 945, also results from an arithmetic mistake. Option C is correct because it includes every number from 91 through 100 exactly once. Option D, 965, is too large and may result from adding an extra amount. Memory cue: for equally spaced numbers, sum = number of terms × average.

Related tags

SequencesPartial-SumsArithmetic-SeriesNatural-NumbersSum Of First N Natural NumbersSequences And ProgressionsMathematicsClass 9 Mcq

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