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What is \(\frac{1}{4}\) of the sum of the first (40) natural numbers?

Answer and explanation

Correct answer: 205

The sum of the first \(n\) natural numbers is \(\frac{n(n+1)}{2}\). For \(n=40\), the sum is \(\frac{40\times41}{2}=820\). One-fourth of this is \(\frac{820}{4}=205\), so option B is correct. A value such as 195 results from an error in finding the sum or dividing it. Exam tip: first calculate the total using \(\frac{n(n+1)}{2}\), then take the required fraction.

Related tags

Sequences And ProgressionsNatural NumbersSum FormulaArithmetic CalculationFractionsSum Of First N Natural NumbersMathematicsClass 9 Mcq

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