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If (S_n=2850), what will be the value of (S_{n-5})?

Answer and explanation

Correct answer: 2485

The sum of the first \(n\) natural numbers is \(S_n=\frac{n(n+1)}{2}\). From \(\frac{n(n+1)}{2}=2850\), we get \(n=75\). Therefore, \(S_{n-5}=S_{70}=\frac{70\times71}{2}=2485\). The value 2556 is \(S_{71}\), so it is not correct here. Exam tip: first find \(n\) from the given sum, then calculate the sum for the required index.

Related tags

Sequences And ProgressionsSum Of Natural NumbersTriangular NumbersAlgebraic ReasoningClass 9 MathematicsSum Of First N Natural NumbersMathematicsClass 9 Mcq

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