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Which formula represents the sum of the first n natural numbers, that is, from 1 to n?

Answer and explanation

Correct answer: \(\frac{n(n+1)}{2}\)

The sum of the first n natural numbers is \(S_n=\frac{n(n+1)}{2}\). Pairing terms gives 1+n, 2+(n-1), and so on, each totaling \(n+1\). \(\frac{n(n-1)}{2}\) is the sum only up to \(n-1\). Exam tip: check the last term before selecting a formula.

Related tags

Natural NumbersSum FormulaSequencesProgressionsAlgebraic IdentitiesClass 9 MathematicsSum Of First N Natural NumbersSequences And Progressions

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