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If (S_n=666), what will be (S_{n+1})?

Answer and explanation

Correct answer: 703

The sum of the first n natural numbers is \(S_n=\frac{n(n+1)}{2}\). From \(\frac{n(n+1)}{2}=666\), we get \(n=36\), since \(S_{36}=666\). Therefore, \(S_{n+1}=S_{37}=666+37=703\). The value 693 would result from adding 27, but the next natural number here is 37. Exam tip: use \(S_{n+1}=S_n+(n+1)\) directly.

Related tags

Sequences And ProgressionsSum Of Natural NumbersTriangular NumbersAlgebraGrade 9 MathematicsSum Of First N Natural NumbersMathematicsClass 9 Mcq

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