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An exam asked the value of (1+2+3+\cdots+95). What is the correct answer?

Answer and explanation

Correct answer: 4560

The sum of the first \(n\) natural numbers is \(\frac{n(n+1)}{2}\). Here, \(n=95\), so \(1+2+\cdots+95=\frac{95\times96}{2}=95\times48=4560\). A value such as 4655 can result from an incorrect multiplication or addition. Exam tip: whenever the sum from \(1\) to \(n\) is asked, apply \(\frac{n(n+1)}{2}\) directly.

Related tags

Sequences And ProgressionsNatural NumbersSum FormulaArithmetic SeriesClass 9 MathematicsSum Of First N Natural NumbersMathematicsClass 9 Mcq

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