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How much is the sum of the first (49) natural numbers?

Answer and explanation

Correct answer: 1225

The sum of the first \(n\) natural numbers is \(\frac{n(n+1)}{2}\). Putting \(n=49\), we get \(\frac{49\times 50}{2}=49\times 25=1225\). Hence, 1225 is the correct answer. A value such as 1215 may result from an incorrect multiplication or addition. Exam tip: use \(\frac{n(n+1)}{2}\) for the sum from \(1\) to \(n\).

Related tags

Natural NumbersSum Of N Natural NumbersArithmetic ProgressionNumber SeriesClass 9 MathematicsSum Of First N Natural NumbersSequences And ProgressionsMathematics

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