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What is the sum of the first (46) natural numbers?

Answer and explanation

Correct answer: 1081

The sum of the first \(n\) natural numbers is \(\frac{n(n+1)}{2}\). Substituting \(n=46\), we get \(\frac{46\times47}{2}=23\times47=1081\). Therefore, 1081 is correct. A value such as 1071 can result from an error in multiplication or subtraction. Exam tip: when \(n\) is even, divide it by 2 first to simplify the calculation.

Related tags

Sequences And ProgressionsNatural NumbersSum FormulaArithmetic CalculationClass 9 MathematicsSum Of First N Natural NumbersMathematicsClass 9 Mcq

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