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What is the value of (1+2+3+\cdots+43)?

Answer and explanation

Correct answer: 946

The sum of the first \(n\) natural numbers is \(\frac{n(n+1)}{2}\). Here, \(n=43\), so \(\frac{43\times44}{2}=43\times22=946\). A value such as 936 results from an arithmetic error in multiplication or division. Exam tip: For the sum from \(1\) to \(n\), use \(\frac{n(n+1)}{2}\).

Related tags

Sequences And ProgressionsNatural NumbersSum Of Natural NumbersArithmetic SeriesClass 9 MathematicsSum Of First N Natural NumbersMathematicsClass 9 Mcq

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