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In this Class 9 Mathematics topic from the Number Systems chapter, students learn how numbers are expressed in decimal form and how decimal expansions relate to rational and irrational numbers. They examine terminating and non-terminating decimals, identify repeating patterns, and connect decimal representations with fractions. The topic builds accuracy in comparing, interpreting, and converting numerical forms while strengthening understanding of the structure and properties of real numbers.
TOPIC PRACTICE
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Up to 25 questions from this page. Select your focus, then start.
25 questions
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Easy · Level 2View options
\(\frac{7}{40}\)
\(\frac{5}{12}\)
\(\frac{11}{18}\)
\(\frac{13}{30}\)
Easy · Level 2View options
(\frac{7}{3})
(\frac{5}{6})
(\frac{9}{14})
(\frac{11}{40})
Easy · Level 2View options
0.375
\(0.121212\ldots\)
\(0.1010010001\ldots\)
2.5
Easy · Level 2View options
(4)
(\frac{4}{10})
(\frac{4}{100})
(\frac{4}{1000})
Easy · Level 2View options
It is equal to \(0.125\) and is rational.
It is irrational because its decimal expansion continues indefinitely.
It will be rational only when the zeros after the decimal point stop.
It is greater than \(0.125\) because it has more digits.
Easy · Level 2View options
(\frac{4}{10})
(\frac{4}{100})
(\frac{40}{10})
(\frac{1}{4})
Easy · Level 2View options
Tenths (दसवाँ)
Hundredths (सौवाँ)
Thousandths (हजारवाँ)
Ones (इकाई)
Easy · Level 2View options
(0.07)
(7.10)
(0.7)
(70.0)
Easy · Level 2View options
(0.06)
(0.60)
(6.0)
(0.006)
Easy · Level 2View options
\(\frac{2}{9}\)
\(\frac{2}{10}\)
\(\frac{1}{2}\)
\(\frac{9}{2}\)
Easy · Level 2View options
1.25
0.89
1.00
2.09
Easy · Level 2View options
\(\frac{3}{8}\)
\(\frac{7}{12}\)
\(\frac{11}{25}\)
\(\frac{13}{40}\)
Easy · Level 2View options
(0.4)
(4)
(40)
(0.004)
Easy · Level 2View options
(0.1010010001\ldots)
(2.2360679\ldots) without repetition
(0.\overline{45})
(3.14159265\ldots) without repetition
Easy · Level 2View options
(\frac{9}{10})
(\frac{9}{100})
(\frac{90}{100})
(\frac{1}{9})
Easy · Level 2View options
(\frac{3}{5})
(\frac{7}{8})
(\frac{1}{6})
(\frac{11}{25})
Easy · Level 2View options
(\frac{8}{10})
(\frac{8}{100})
(\frac{8}{1000})
(8)
Easy · Level 2View options
0.03
0.29
0.300
0.31
Easy · Level 2View options
0.13
1.3
13.00
0.013
Easy · Level 2View options
(0.070)
(0.7)
(0.0700)
(\frac{7}{100})
Easy · Level 2View options
(6\frac{1}{4})
(6\frac{1}{2})
(6\frac{3}{4})
(6\frac{25}{10})
Easy · Level 2View options
(2.49)
(2.56)
(2.75)
(2.07)
Easy · Level 2View options
The statement is correct; the decimal expansion is non-terminating recurring.
The statement is false; \(\frac{7}{40}\) is an irrational number.
The statement is false; the decimal expansion terminates and is \(0.175\).
The statement is correct; only denominators that are powers of 10 give terminating decimals.
Easy · Level 2View options
1
2
3
4
Easy · Level 2View options
(5.9)
(5.10)
(5.090)
(5.08)
Question 1EasyLevel 2
Which of the following fractions has a terminating decimal expansion?
Correct answer: A
For \(\frac{7}{40}\), the denominator is \(40=2^3\times5\), so its decimal expansion terminates. The other denominators contain 3. Exam tip: first reduce the fraction to lowest terms.
Which fraction will have a terminating decimal expansion?
Correct answer: D
In (\frac{11}{40}), the denominator (40=2^3\times5), so the decimal is terminating. Exam tip: check whether the denominator has only (2) and (5) as prime factors.
Which of the following decimal expansions is non-terminating recurring?
Correct answer: B
In \(0.121212\ldots\), the block 12 repeats endlessly, so it is non-terminating recurring. In \(0.1010010001\ldots\), no fixed block repeats. Exam tip: look for a repeating digit pattern.
(4) is in the hundredths place, so its place value is (\frac{4}{100}). Exam tip: after the decimal point, the first place is tenths and the second is hundredths.
A student says that \(0.125000\ldots\) is irrational because it has infinitely many zeros. Which is the correct correction to the statement?
Correct answer: A
\(0.125000\ldots=\frac{125}{1000}=\frac18\), so it is rational and has a terminating decimal expansion. Infinitely many trailing zeros do not change the value. Exam tip: remove trailing zeros before classifying a decimal.
The governing concept is decimal place value. In a number such as 2.305, the first digit to the right of the decimal point is in the tenths place, the second is in the hundredths place, and the third is in the thousandths place. Reading 2.305 from left to right after the decimal gives 3, 0, and 5. Thus 3 is in the tenths place, 0 is in the hundredths place, and 5 is in the thousandths place. Therefore option B is correct. The digit 2 is in the ones place, so option D is incorrect. The zero contributes no quantity by itself, but it is important as a place holder because it preserves the hundredths position and distinguishes 2.305 from numbers such as 2.35 or 2.035.
A fraction with denominator 10 represents tenths. The numerator 7 means seven tenths, and seven tenths is written as 0.7 in decimal notation. The zero before the decimal point shows that the value is less than one. Thus the correct choice is C, 0.7. The other choices do not represent seven tenths: 0.07 is seven hundredths, 7.10 is greater than seven, and 70.0 is seventy.
To convert directly, divide the numerator by the denominator: 7 ÷ 10 = 0.7. Equivalently, move the decimal point in 7 one place to the left because division by 10 reduces the value tenfold. Therefore, \(\frac{7}{10}=0.7\). The denominator tells us the place value: 10 gives one digit after the decimal point, so 0.7 is the required representation.
Let \(x=0.\overline{2}=0.222\ldots\). Multiplying by 10 gives \(10x=2.222\ldots\). Subtracting the first equation from the second gives \(9x=2\), so \(x=\frac{2}{9}\). Therefore, option A is correct. Exam tip: a decimal with one repeating digit, such as \(0.\overline{a}\), equals \(\frac{a}{9}\), not \(\frac{a}{10}\).
The governing concept is comparison of decimal numbers by their whole-number parts and fractional parts. A positive number that is less than 1 must have whole-number part 0 and a positive decimal part. Among the choices, 0.89 satisfies the inequality 0 < 0.89 < 1, so option B is correct. The number 1.25 is greater than 1, while 1.00 is exactly equal to 1 and therefore is not less than 1. The number 2.09 is also greater than 1. A quick method is to inspect the digit before the decimal point: a positive decimal strictly between zero and one begins with 0, and at least one digit after the decimal must be positive. This confirms that 0.89, and only 0.89 among the choices, meets both conditions.
Which of the following rational numbers has a non-terminating recurring decimal expansion?
Correct answer: B
For \(\frac{7}{12}\), \(12=2^2\times3\); factor 3 makes the decimal recur. A terminating decimal has only 2 and/or 5 in its reduced denominator. Exam tip: factor the denominator first.
Which number is equal to the decimal expansion (4.000)?
Correct answer: B
The number equal to 4.000 is 4, so B is correct. Decimal notation allows zeros to be written to the right of the last nonzero digit without changing the value: 4.000=4.000−0.000=4. The digit 4 is in the units place, while the decimal zeros represent zero tenths, hundredths, and thousandths. A, 0.4, means four tenths and is ten times smaller. C, 40, is ten times larger and has a different units value. D, 0.004, means four thousandths, also much smaller. Do not confuse trailing zeros after a decimal with a change in place value; zeros after the last nonzero decimal digit are harmless. Memory cue: 7.0, 7.00 and 7 have the same value.
For comparison, write 0.3 as 0.30. In 0.31, the tenths digit is the same as in 0.30, but the hundredths digit is 1, which is greater than 0. Therefore, 0.31 > 0.30. The value of 0.300 is equal to 0.3, not greater. Exam tip: add zeros at the end of decimals when needed to make the number of decimal places equal.
The governing concept is place value when the denominator is a power of ten. Since 100 has two zeros, 13/100 means thirteen hundredths, which is written as 0.13. Equivalently, dividing 13 by 100 moves the decimal point two places to the left: 13.00 becomes 0.13. Therefore option A is correct. Option B, 1.3, represents 13/10 rather than 13/100. Option C, 13.00, has value 13, and option D, 0.013, represents thirteen thousandths, or 13/1000. The two digits after the decimal point in 0.13 correspond exactly to the hundredths denominator. The repeated value after the slash in option A does not change the fact that it is the only correct choice.
The direct answer is option A,
\(6\frac{1}{4}\). Separate the whole and decimal parts:
\(6.25=6+0.25\). Since
\(0.25=25/100=1/4\) after cancelling the common factor 25, we get
\(6.25=6\frac{1}{4}\). As an improper fraction, this is
\(25/4\), which confirms the mixed form. Option A is correct. Option B,
\(6\frac{1}{2}\), equals 6.5, not 6.25. Option C,
\(6\frac{3}{4}\), equals 6.75, so it is too large. Option D,
\(6\frac{25}{10}\), is not the correct mixed-number conversion; also
\(25/10=2.5\), so its value would be 8.5, and the fraction is not simplified. Memory cue: 0.25 is one quarter.
The direct answer is option B,
\(2.56\). A number lies between two numbers when it is greater than the smaller number and less than the larger number. Write the endpoints with equal decimal places:
\(2.5=2.50\) and
\(2.7=2.70\). Now compare:
\(2.50<2.56<2.70\), so 2.56 is between them. Option A,
\(2.49\), is less than 2.50, so it lies below the interval. Option B is correct. Option C,
\(2.75\), is greater than 2.70, so it lies above the interval. Option D,
\(2.07\), is also less than 2.50. Adding a zero to the right of a decimal does not change its value, so this comparison method is safe. Exam cue: align decimal places before comparing.
A student says, “The decimal expansion of \(\frac{7}{40}\) will be non-terminating because 40 is not a power of 10.” Which option about this statement is correct?
Correct answer: C
The claim is false. Since \(40=2^3\times5\), its denominator has only 2 and 5 as prime factors; hence \(7\div40=0.175\) terminates. Exam tip: factor the reduced denominator first.
The governing concept is the definition of decimal places: they are the digits written to the right of the decimal point. In 0.375, the digits after the decimal point are 3, 7, and 5. Counting them gives three decimal places, so option C is correct. The zero before the decimal point belongs to the whole-number part and must not be counted as a decimal place. Option A would be correct for a number such as 0.3, and option B would fit 0.37. Option D would require four digits after the decimal point, for example 0.3750. A trailing zero can indicate an additional written decimal place even when it does not change the numerical value, but the given number is written as 0.375 and visibly contains exactly three digits after the point.
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