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A machine's value is (V(y)=c-4200y). If (V(4)=53200), what will (V(11)) be?

Answer and explanation

Correct answer: 23800

Given \(V(y)=c-4200y\). Using \(V(4)=53200\), we get \(c-4200\times4=53200\), so \(c=70000\). Now \(V(11)=70000-4200\times11=23800\). Therefore, 23800 is correct. A nearby option such as 28000 can result from using an incorrect number of years or making an arithmetic error in the depreciation term. Exam tip: first find the constant \(c\) from the given value, then substitute the required value of \(y\).

Related tags

Linear DecayPolynomialsLinear ExpressionValue DepreciationSubstitutionLinear Growth And DecayIntroduction To PolynomialsMathematics

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