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If (C(t)=55+kt) and (C(12)-C(5)=105), what is (k)?यदि (C(t)=55+kt) और (C(12)-C(5)=105), तो (k) क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: 1515
Given \(C(t)=55+kt\), we have \(C(12)=55+12k\) and \(C(5)=55+5k\). Thus, \(C(12)-C(5)=(55+12k)-(55+5k)=7k\). Since this difference is 105, \(7k=105\), so \(k=15\). If \(k=21\), the difference would be \(7\times21=147\), not 105. Exam tip: when subtracting two values of a linear expression, the constant term 55 cancels out.दिया है: \(C(t)=55+kt\)। अतः \(C(12)=55+12k\) और \(C(5)=55+5k\)। इसलिए \(C(12)-C(5)=(55+12k)-(55+5k)=7k\)। चूँकि यह अंतर 105 है, \(7k=105\), इसलिए \(k=15\)। विकल्प 21 लेने पर अंतर \(7\times21=147\) आता, जो दिया गया 105 नहीं है। परीक्षा टिप: रैखिक व्यंजक के दो मानों का अंतर लेते समय स्थिर पद 55 कट जाता है।
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