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A machine's value is (V(y)=c-3200y). If (V(5)=44000), what will (V(11)) be?

Answer and explanation

Correct answer: 24800

Given \(V(y)=c-3200y\). Substituting \(V(5)=44000\) gives \(c-3200\times5=44000\), so \(c=60000\). Hence, \(V(11)=60000-3200\times11=60000-35200=24800\). Option B, 28000, would result from using an incorrect value in place of 11. Exam tip: first find \(c\) using the given condition, then substitute the required value of \(y\).

Related tags

Linear PolynomialLinear DecayDepreciationSubstitutionAlgebraic EvaluationLinear Growth And DecayIntroduction To PolynomialsMathematics

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