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If (F(t)=65+rt) and (F(4)=F(12)-96), what is (r)?यदि (F(t)=65+rt) और (F(4)=F(12)-96), तो (r) क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: 1212
Given \(F(t)=65+rt\), we have \(F(4)=65+4r\) and \(F(12)=65+12r\). Substituting these into \(F(4)=F(12)-96\) gives \(65+4r=65+12r-96\). Hence, \(8r=96\), so \(r=12\). For example, if \(r=14\), then \(F(12)-F(4)=8\times14=112\), not 96. Exam tip: when subtracting two values of a linear function, the constant term 65 cancels out.दिया है कि \(F(t)=65+rt\)। अतः \(F(4)=65+4r\) और \(F(12)=65+12r\) होगा। शर्त \(F(4)=F(12)-96\) रखने पर \(65+4r=65+12r-96\), इसलिए \(8r=96\) और \(r=12\) मिलता है। विकल्प 14 लेने पर अंतर \(F(12)-F(4)=8\times14=112\) होगा, 96 नहीं। परीक्षा टिप: रैखिक फलन के दो मानों का अंतर निकालते समय स्थिर पद 65 कट जाता है।
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