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A machine's value is (V(y)=c-2200y). If (V(4)=31200), what will (V(9)) be?

Answer and explanation

Correct answer: 20200

Given \(V(y)=c-2200y\). Substituting \(V(4)=31200\) gives \(c-2200(4)=31200\), so \(c=40000\). Therefore, \(V(9)=40000-2200(9)=40000-19800=20200\). Hence, 20200 is correct. The value 22400 would result from using 8 instead of 9. Exam tip: first find the constant \(c\) from the given value, then substitute the required value of \(y\).

Related tags

Linear DecayLinear PolynomialValue DepreciationSubstitutionAlgebraic EvaluationLinear Growth And DecayIntroduction To PolynomialsMathematics

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