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Two models are (C(t)=140-8t) and (D(t)=110-3t). What is the correct comparison at (t=6)?

Answer and explanation

Correct answer: \(C(6)=D(6)\)

Substituting \(t=6\), \(C(6)=140-8\times6=92\) and \(D(6)=110-3\times6=92\). Hence, the two model values are equal, so \(C(6)=D(6)\). Options A and B are incorrect because neither value is greater than the other, and both values are not zero. Exam tip: evaluate each expression separately at the given value of \(t\) before comparing them.

Related tags

Linear FunctionsPolynomialsSubstitutionComparisonEqualityMathematicsLinear Growth And DecayIntroduction To Polynomials

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