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If (K(t)=160-8t), what is the value of (K(0)-K(12))?यदि (K(t)=160-8t), तो (K(0)-K(12)) का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: 9696
Here, K(0)=160-8(0)=160 and K(12)=160-8(12)=64. Therefore, K(0)-K(12)=160-64=96. Option 64 is the value of K(12), not the difference. Exam tip: in linear decay, 8×12=96 directly gives the total decrease.यहाँ K(0)=160-8(0)=160 और K(12)=160-8(12)=64 है। अतः K(0)-K(12)=160-64=96। विकल्प 64, K(12) का मान है, अंतर का नहीं। परीक्षा टिप: रैखिक ह्रास में 8×12=96 सीधे कुल कमी देता है।
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