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Two models are (C(t)=100-6t) and (D(t)=85-3t). What is the correct comparison at (t=5)?

Answer and explanation

Correct answer: \(C(5)=D(5)\)

Substituting \(t=5\), we get \(C(5)=100-6\times5=70\) and \(D(5)=85-3\times5=70\). Therefore, the two model values are equal, so \(C(5)=D(5)\) is correct. They are not zero; their common value is 70. Exam tip: evaluate both expressions at the given value of \(t\) before comparing them.

Related tags

Linear FunctionsPolynomial EvaluationLinear DecayComparison Of ValuesClass 9 MathematicsLinear Growth And DecayIntroduction To PolynomialsMathematics

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