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A battery remains (B(h)=96-6h) percent. When will the battery be (48%)?

Answer and explanation

Correct answer: 8

For the battery percentage to be 48, set \(B(h)=48\): \(96-6h=48\). Thus, \(6h=48\), so \(h=8\). Therefore, the battery will be 48% after 8 hours. At 6 hours, it is \(96-36=60\)% remaining, so that nearby option is incorrect. Exam tip: In a linear decay problem, equate the function to the target value and solve for the variable.

Related tags

Linear DecayLinear EquationsBattery PercentagePolynomialsAlgebraLinear Growth And DecayIntroduction To PolynomialsMathematics

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