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If (T(t)=100-12t), what is the value of (T(1)-T(3))?

Answer and explanation

Correct answer: 24

Given \(T(t)=100-12t\), \(T(1)=100-12=88\) and \(T(3)=100-36=64\). Hence, \(T(1)-T(3)=88-64=24\). Option A, 12, is only the decrease per unit time; the interval from 1 to 3 is 2 units. Exam tip: Find each function value separately before subtracting them.

Related tags

Linear FunctionLinear DecayFunction EvaluationPolynomialsDifferenceLinear Growth And DecayIntroduction To PolynomialsMathematics

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