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A battery remains (B(h)=100-10h) percent. How much battery will remain at (h=6)?

Answer and explanation

Correct answer: 40%

The given function is \(B(h)=100-10h\). Substituting \(h=6\), \(B(6)=100-10(6)=100-60=40\). Therefore, 40% battery remains. The option 50% is incorrect because the decrease in 6 hours is \(10\times6=60\) percentage points, not 50. Exam tip: In linear-decay questions, substitute the given value of \(h\) first, then multiply and subtract.

Related tags

Linear DecayLinear FunctionSubstitutionBattery PercentagePolynomialsLinear Growth And DecayIntroduction To PolynomialsMathematics

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