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In Class 9 Mathematics, under Introduction to Polynomials, Definition of a Polynomial explains expressions in which variables have only non-negative integer powers. Students learn to distinguish polynomials from expressions containing negative, fractional, or other invalid exponents, identify constant and zero polynomials, and recognise polynomials by their highest power and basic type.
TOPIC PRACTICE
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Medium · Level 4View options
x⁵ − 2x² + 6
x⁵ᐟ² + 1
x⁻⁵ + 2
1/x⁵ + 3
Medium · Level 4View options
x^2+x
4x^7
x^3-1
2x^2+3x+5
Medium · Level 4View options
Linear monomial
Quadratic binomial
Cubic trinomial
Constant polynomial
Medium · Level 4View options
\(x^4-4x+1\)
\(5x^{-4}+2x\)
\(x^0+4x\)
\(8x^3+7\)
Medium · Level 4View options
\(x^4+x^2+1\)
\(2x^3-x^2+x-6\)
\(7x^2-5\)
\(9x\)
Medium · Level 4View options
0
1
2
6
Medium · Level 4View options
(x^4+x^2+1)
(x^{-4}+x^2)
(\frac{1}{x^3}+x)
(x^{3/2}+x)
Medium · Level 4View options
Negative integer
Zero or positive integer
Always fraction
Always (1)
Medium · Level 4View options
(x^2+3x-8)
(x^{-2}-8)
(\sqrt{x}-8)
(\frac{1}{x}-8)
Medium · Level 4View options
Quadratic trinomial
Cubic four-term polynomial
Linear binomial
Constant polynomial
Medium · Level 4View options
\(x^5+2x^3-7\)
\(x^5+2x^{-3}-7\)
\(x^{5/3}+2x^3-7\)
\(x^5+\frac{2}{x^3}-7\)
Medium · Level 4View options
(2.5x^2-3x+1)
(x^{-1}+2.5)
(\sqrt{x}+2.5)
(\frac{x+1}{x})
Medium · Level 4View options
Because it contains the term \(x^2\)
Because \(\frac{1}{x}=x^{-1}\) has a negative exponent of \(x\)
Because its constant term is \(4\)
Because it has three terms
Medium · Level 4View options
(x^2+1) because powers are (2) and (0)
(x^{-2}+1) because power is (-2)
(\sqrt{x}+1) because there is a radical sign
(\frac{1}{x}+1) because (x) is in denominator
Medium · Level 4View options
yx³ + 2x − 5
y/x + 2
x⁻² + y
√x + y
Medium · Level 4View options
It is a linear trinomial
It is a quadratic binomial
It is a cubic trinomial
It is not a polynomial
Medium · Level 4View options
5
2
3
0
Medium · Level 4View options
(x^2+8)
(2^x+x)
(5x^4-1)
(\sqrt{2}x+3)
Medium · Level 4View options
3
2
1
0
Medium · Level 4View options
Because ∛x = x^(1/3)
Because it has x^2
Because it has two terms
Because it has addition
Medium · Level 4View options
2x^3 + 5x + 1
9x^2 - 4
x^4 + x^2 + x
x/(x + 1)
Medium · Level 4View options
3
4
5
9
Medium · Level 4View options
It is not a polynomial because one of its coefficients is \(\sqrt{5}\)
It is not a polynomial because its constant term is negative
It is the zero polynomial
It is a polynomial in \(y\)
Medium · Level 4View options
Linear trinomial polynomial
Quadratic binomial polynomial
Cubic trinomial polynomial
Constant polynomial
Medium · Level 4View options
\(z^2+1\)
\(\frac{1}{z}+2\)
\(14\)
\(8z-3\)
Question 1MediumLevel 4
Which expression is a polynomial in x and has highest power 5?
Correct answer: A
The governing concept is the definition and degree of a polynomial. A polynomial in x may contain only non-negative integer powers of x. In option A, the exponents are 5, 2, and 0. All are non-negative integers, and the greatest exponent is 5, so x⁵ − 2x² + 6 is a polynomial of degree 5. Option B has exponent 5/2, which is fractional and therefore invalid. Option C has the negative exponent −5. Option D can be rewritten as x⁻⁵ + 3, so it also contains a negative exponent. Those expressions are not polynomials in x. Hence option A is the only choice satisfying both requirements: being a polynomial and having highest power 5.
A polynomial containing exactly one term is called a monomial. \(4x^7\) has only one term, so it is the correct answer. \(x^2+x\) and \(x^3-1\) each have two terms. Exam tip: Count terms separated by plus (+) or minus (−) signs.
The expression \(x^2-9\) has two terms, \(x^2\) and \(-9\), so it is a binomial. Its highest exponent is \(2\), hence its degree is 2 and it is quadratic. Therefore, it is a quadratic binomial. A cubic trinomial would need degree 3 and three terms. Exam tip: classify a polynomial by checking the number of terms and the highest exponent separately.
Which expression is not a polynomial because it contains (x^{-4})?
Correct answer: B
\(5x^{-4}+2x\) is not a polynomial because the exponent of \(x\) is \(-4\). In a polynomial, exponents of variables must be zero or positive integers. Since \(x^0=1\), option C is a polynomial; a zero exponent is allowed, but a negative exponent is not. Exam tip: An expression with a negative, fractional, or irrational exponent of a variable is not a polynomial.
\(2x^3-x^2+x-6\) has four terms: \(2x^3\), \(-x^2\), \(x\), and \(-6\). Terms of a polynomial are separated by plus or minus signs. Option A has only three terms, so it is not correct. Exam tip: Always count the constant term as a separate term.
The degree of a polynomial is the greatest exponent of the variable among its non-zero terms. Here, 6x^2 has exponent 2 and -5x has exponent 1. The constant term 0 does not affect the degree, so the answer is 2. Note that 6 is a coefficient, not the degree. Exam tip: Find the non-zero term with the highest power of the variable.
According to the definition of a polynomial, how should the power of the variable be?
Correct answer: B
A polynomial is an algebraic expression made from terms whose variable powers are whole numbers starting at zero: \\(0,1,2,3,\\ldots\\). The coefficients may be real numbers, including integers, fractions, and terminating or non-terminating decimal values. A variable may have power zero, which represents a constant term, but negative or fractional powers are not allowed in the usual school definition of a polynomial.
Thus option B correctly says that the power must be zero or a positive integer. Option A is wrong because a negative power places the variable in a denominator. Option C is wrong because a fractional power such as \\(x^{1/2}\\) is a radical expression, and option D is too restrictive: the power need not always be 1. Therefore, B is correct.
Which expression is a polynomial with a negative constant term?
Correct answer: A
A polynomial in \\(x\\) may have positive, zero, or negative coefficients. The sign of a coefficient does not decide whether an expression is a polynomial. What matters is that the powers of \\(x\\) are non-negative whole numbers. In \\(x^2+3x-8\\), the powers are \\(2\\), \\(1\\), and \\(0\\), so every term is permitted, and the constant term is -8.
Therefore, option A is the required expression. The other choices contain \\(x^{-2}\\), \\(\\sqrt{x}=x^{1/2}\\), or \\(1/x=x^{-1}\\). These involve a negative or fractional power and therefore are not polynomials in \\(x\\), even though each also includes the negative constant -8. A negative constant is entirely acceptable in a polynomial.
Which is the correct identification of (p(x)=2x^3+5x^2-x+4)?
Correct answer: B
The highest exponent of x is 3 because the polynomial contains the term 2x^3; therefore, it is a cubic polynomial. It has four terms: 2x^3, 5x^2, -x, and 4. Hence, it is a cubic four-term polynomial. A quadratic polynomial has highest degree 2, so option A is not correct. Exam tip: identify the degree from the highest power of x, and count terms separated by plus or minus signs.
In which expression are the powers of (x) (5), (3), and (0)?
Correct answer: A
In \(x^5+2x^3-7\), the powers of \(x\) are \(5\), \(3\), and \(0\), respectively, because the constant term \(-7\) can be written as \(-7x^0\). In option B, the power of \(x\) is \(-3\), while option C has the fractional power \(5/3\). In option D, \(\frac{2}{x^3}=2x^{-3}\). Exam tip: a constant term always has the variable raised to power \(0\).
Which expression is a polynomial with real coefficients?
Correct answer: A
A polynomial with real coefficients must have real-number coefficients and only non-negative integer powers of the variable. Real coefficients can include 2.5, because every terminating decimal is a real number. The important test is whether the variable powers are 0, 1, 2, and so on, with no variable in a denominator or under a radical.
In option A, \\(2.5x^2-3x+1\\) has real coefficients and powers 2, 1, and 0, so it is a polynomial. Option B contains \\(x^{-1}\\), option C contains the fractional power \\(x^{1/2}\\), and option D has x in the denominator. These violate the required form. Therefore, option A is correct.
In a polynomial, the exponents of a variable must be non-negative integers such as \(0,1,2,\ldots\). Here, \(\frac{1}{x}=x^{-1}\), so the exponent of \(x\) is \(-1\); hence the expression is not a polynomial. The term \(x^2\) and the constant \(4\) are valid polynomial terms, and having three terms is not a restriction. Exam tip: If a variable occurs in the denominator, rewrite it using a negative exponent and check it.
Which option gives a correct example-explanation of a polynomial?
Correct answer: A
A polynomial may contain several terms, constants, and numerical coefficients, provided every variable power is a non-negative integer. The power 0 is allowed because a constant can be viewed as a term involving \\(x^0\\). Therefore, the presence of a constant or addition is not a problem. What matters is the form of each power of x.
In \\(x^2+1\\), the first term has power 2 and the constant term has power 0. Both powers are valid, so this is a polynomial. The other choices contain \\(x^{-2}\\), \\(\sqrt{x}=x^{1/2}\\), or \\(1/x=x^{-1}\\); these involve a negative or fractional power of x. Thus option A gives the correct example and explanation.
Which expression is a polynomial in x but includes y as a coefficient-like quantity?
Correct answer: A
The governing concept is that a polynomial may be considered in one specified variable while other symbols are treated as constants or parameters. In option A, yx³ + 2x − 5 is a polynomial in x: the powers of x are 3, 1, and 0, all non-negative integers. The symbol y acts as a coefficient-like parameter multiplying x³, so its presence does not violate the polynomial condition when x is the variable under consideration. Option B contains y/x = yx⁻¹, option C contains x⁻², and option D contains √x = x^(1/2). Each of those has an invalid power of x. Therefore option A is the only correct answer. If the question instead treated both x and y as variables jointly, the expression would still be a polynomial in two variables.
In \(x^3-2x+5\), the highest power of the variable \(x\) is 3, so its degree is 3 and it is a cubic polynomial. It has three terms: \(x^3\), \(-2x\), and \(5\); therefore, it is also a trinomial. Hence, it is a cubic trinomial. A quadratic polynomial would have highest degree 2. Exam tip: find the degree from the highest exponent, then count the terms separately.
If (p(x)=0x^5+4x^2-3x+8), what will be the degree of (p(x))?
Correct answer: B
The degree of a polynomial is the greatest exponent of the variable having a non-zero coefficient. Here, the coefficient of 0x^5 is zero, so this term does not determine the degree. Among the remaining non-zero terms, 4x^2 has the greatest exponent; therefore, the degree of p(x) is 2. Option 5 is incorrect because the coefficient of x^5 is 0. Exam tip: remove zero-coefficient terms before finding the degree.
If (a=0) in (p(x)=ax^3+2x-1), what will be the degree of the polynomial?
Correct answer: C
On substituting \(a=0\), the term \(ax^3\) becomes 0. Thus, \(p(x)=2x-1\). The highest power of \(x\) present is 1, so the degree of the polynomial is 1. It is not 3 because the coefficient of \(x^3\) is zero. Exam tip: Ignore terms whose coefficients become zero while finding the degree.
The governing concept is the definition of a polynomial in one variable. In a polynomial, the exponent of the variable in every term must be a non-negative integer such as 0, 1, 2, or 3. The cube root of x can be rewritten as x^(1/3), so the expression becomes x^2 + x^(1/3). Although x^2 is an acceptable polynomial term, the exponent 1/3 is fractional and therefore violates the polynomial definition. Thus option A states the correct reason. Having two terms is allowed, and addition is also allowed in a polynomial. The presence of x^2 is not a problem either. The issue is specifically the fractional exponent on the variable, not the number of terms or the operation joining them.
The governing concept is the structural definition of a polynomial in x. Every term of a polynomial must contain x only with a non-negative integer exponent, and x cannot occur in a denominator. Options A, B, and C satisfy this condition: their powers of x are whole numbers such as 0, 1, 2, 3, or 4. In option D, x/(x + 1), the variable appears in the denominator. This is a rational expression rather than a polynomial, and it is undefined at x = -1. It cannot be represented as a finite sum of terms with only non-negative integer powers of x. Therefore option D is correct. The number of terms and the presence of a constant term do not disqualify the other options.
What is the degree of the polynomial (9t^5-4t^3+2t-1)?
Correct answer: C
The degree of a polynomial is the highest exponent of the variable with a non-zero coefficient. The terms in the given polynomial have exponents 5, 3, 1, and 0. The highest exponent is 5, so the degree is 5. Note that 9 is a coefficient, not the degree. Exam tip: identify the term with the greatest exponent of the variable.
Which statement is correct about \(3y^2+\sqrt{5}y-8\)?
Correct answer: D
In \(3y^2+\sqrt{5}y-8\), the powers of \(y\) are \(2\), \(1\), and \(0\), all of which are non-negative integers. \(\sqrt{5}\) is a real number, so it is a valid coefficient. A negative constant term, \(-8\), also does not prevent an expression from being a polynomial. A zero polynomial has every coefficient equal to zero, which is not true here. Exam tip: to identify a polynomial, check the exponents of the variable; coefficients may be irrational or negative.
Which is the correct identification of (2x^3-5x+4)?
Correct answer: C
In the polynomial \(2x^3-5x+4\), the highest power of \(x\) is \(3\), so it is a cubic polynomial. It has three terms: \(2x^3\), \(-5x\), and \(4\); therefore, it is a trinomial. Hence, it is a cubic trinomial polynomial. A linear polynomial has highest degree 1. Exam tip: first find the highest exponent, then count the terms to classify a polynomial.
In \(8z-3\), the highest power of \(z\) is 1 and the coefficient of \(z\) is non-zero, so it is a linear polynomial. \(14\) is a constant polynomial of degree 0, while \(\frac{1}{z}+2\) is not a polynomial because it contains the negative power \(z^{-1}\). Exam tip: A linear polynomial has the form \(az+b\), where \(a\ne0\).
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