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In Class 9 Mathematics, under Introduction to Polynomials, Definition of a Polynomial explains expressions in which variables have only non-negative integer powers. Students learn to distinguish polynomials from expressions containing negative, fractional, or other invalid exponents, identify constant and zero polynomials, and recognise polynomials by their highest power and basic type.
TOPIC PRACTICE
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Easy · Level 5View options
4, 2, 0
4, 5, 1
2, 1, −1
4, 1/2, 0
Easy · Level 5View options
3
4
5
6
Easy · Level 5View options
Linear polynomial
Quadratic polynomial
Cubic polynomial
Zero polynomial
Easy · Level 5View options
Linear polynomial
Quadratic polynomial
Cubic polynomial
Constant polynomial
Easy · Level 5View options
Quadratic polynomial
Linear polynomial
Cubic polynomial
Constant polynomial
Easy · Level 5View options
Linear polynomial
Quadratic polynomial
Zero polynomial
Constant polynomial
Easy · Level 5View options
Because the constant term is 2
Because the exponent of the variable is fractional
Because it contains an addition sign
Because it has two terms
Easy · Level 5View options
क्योंकि x की एक घात ऋणात्मक है
क्योंकि इसमें रैखिक पद 9x है
क्योंकि इसमें दो पद हैं
क्योंकि पदों के बीच जोड़ का चिह्न है
Easy · Level 5View options
2
4
6
7
Easy · Level 5View options
2
3
4
5
Easy · Level 5View options
\(9x^5\)
\(x^3\)
\(-2\)
\(9\)
Easy · Level 5View options
Polynomial
Not a polynomial
Zero polynomial
Expression without variable
Easy · Level 5View options
Linear polynomial
Quadratic polynomial
Not a polynomial
Constant polynomial
Easy · Level 5View options
14
2
0
\(x^2\)
Easy · Level 5View options
1
2
4
0
Easy · Level 5View options
Yes, because \(x^0=1\), so the expression becomes \(3+5x\), in which the exponents of \(x\) are non-negative integers.
No, because a term containing \(x^0\) cannot occur in a polynomial.
No, because a polynomial must have only one term.
No, because \(5x\) contains the variable \(x\).
Easy · Level 5View options
No, because it has a fractional coefficient
Yes, because the power of (x) is (1)
No, because it has (-3)
No, because it is a binomial
Easy · Level 5View options
Yes, because coefficients can be real and powers are valid
No, because the coefficient is a negative fraction
No, because it has (x^4)
No, because it has three terms
Easy · Level 5View options
\(x^5+6\)
\(x^{\frac{5}{6}}+4\)
\(6x^2+1\)
\(5x+6\)
Easy · Level 5View options
0
1
2
8
Easy · Level 5View options
0
1
5
17
Easy · Level 5View options
\(0\)
\(1\)
\(31\)
Not defined
Easy · Level 5View options
Both have degree (0)
The zero polynomial has degree (1)
The zero polynomial degree is not defined and a non-zero constant has degree (0)
Both are not polynomials
Easy · Level 5View options
\(-5x^6\)
\(3x^4\)
\(-x\)
\(9\)
Easy · Level 5View options
\(4x^3-7x+1\)
\(\frac{3}{x}+2\)
\(\sqrt{x}+5\)
\(x^{-2}+4\)
Question 1EasyLevel 5
Which powers are present in 2x⁴ + 5x² + 1?
Correct answer: A
The governing rule is that the power of a term is the exponent of the variable, while a nonzero constant is treated as having power 0. Thus 2x⁴ contributes power 4, 5x² contributes power 2, and 1 contributes power 0. The coefficient numbers 2 and 5 are not powers, so option A is correct; the other choices confuse coefficients or introduce powers not present.
What is the degree of the polynomial (6x^5-2x^3+x-8)?
Correct answer: C
The degree of a polynomial is the greatest exponent of the variable in any term with a non-zero coefficient. Here, the exponents of the terms are 5, 3, 1, and 0. The greatest exponent is 5, so the degree of the polynomial is 5. The number 6 is a coefficient, not the degree. Exam tip: To find the degree, look for the highest power of the variable.
In \(8x-11\), the highest power of \(x\) is \(1\), so its degree is \(1\). A polynomial with degree \(1\) is called a linear polynomial. A quadratic polynomial has highest power \(2\), so it is not correct here. Exam tip: To identify the type of a polynomial, look for the highest power of the variable.
The highest power of x is 2 because the term 7x^2 is present. Therefore, the degree of this polynomial is 2, so it is a quadratic polynomial. A linear polynomial has degree 1, but this expression also contains an x^2 term. Exam tip: To identify the type of a polynomial, look for the highest exponent of the variable.
The degree of a polynomial is the highest power of its variable with a non-zero coefficient. In \(3x^3-5x+2\), the highest power of \(x\) is 3, so it is a cubic polynomial. The terms \(-5x\) and 2 have degrees 1 and 0 respectively, so they do not affect the degree. Exam tip: To identify the type of a polynomial, first locate the highest power of the variable.
The expression 21 contains no variable, such as x, so its value always remains 21. Therefore, it is a non-zero constant polynomial and has degree 0. A zero polynomial has all its coefficients equal to 0, whereas the constant here is 21. Exam tip: An expression containing only a non-zero number is a constant polynomial.
In a polynomial, every exponent of a variable must be a non-negative integer. Here, the exponent of \(x\) is \(\frac{7}{3}\), which is fractional, so \(x^{\frac{7}{3}}+2\) is not a polynomial. A constant term such as 2, addition, and having two terms do not prevent an expression from being a polynomial. Exam tip: An expression is not a polynomial if a variable has a fractional or negative exponent, or appears in an exponent.
In a polynomial, the exponent of a variable must be 0 or a positive integer. This expression contains x^{-5}, where the exponent of x is -5, so it is not a polynomial. The term 9x is a valid linear term; having two terms or an addition sign does not prevent an expression from being a polynomial. Exam tip: An expression with a negative, fractional, or variable exponent is not a polynomial.
The degree of a polynomial is the greatest exponent of the variable among terms with non-zero coefficients. Here, the exponents are 7, 4, 2, and 0. The greatest exponent is 7, so the degree of the polynomial is 7. The term -6 is a constant term and has degree 0. Exam tip: To find the degree, look for the highest power of the variable, not the coefficient.
Terms of a polynomial are algebraic parts separated by addition or subtraction. Here the terms are \(5x^4\), \(-3x^2\), \(x\), and \(-12\). Therefore, there are 4 terms. Note that \(-3x^2\) is one complete term; the negative sign is part of its coefficient. Exam tip: Count each complete algebraic part separated by + or − as one term.
In (9x^5+x^3-2), which term has the highest power?
Correct answer: A
The degrees of the terms are \(5\), \(3\), and \(0\), respectively. The greatest power is \(5\), which occurs in the term \(9x^5\). The term \(x^3\) has power \(3\), so it is not the highest. Exam tip: Find a term’s degree by looking at the exponent of its variable; a constant term has degree \(0\).
This is a polynomial because the powers of the variable \(x\) are \(2\), \(1\), and \(0\), all of which are non-negative integers. Although \(\sqrt{7}\) is irrational, it is a real number and can be a valid coefficient of \(x\). The presence of \(\sqrt{7}\) does not make the expression a non-polynomial. Exam tip: In a polynomial, variable exponents must be \(0,1,2,\ldots\), while coefficients may be any real numbers.
The correct answer is not a polynomial. Since \(\sqrt{x}=x^{\frac{1}{2}}\), the exponent of \(x\) in the expression is \(\frac{1}{2}\). In a polynomial, variable exponents must be zero or positive integers; fractional exponents are not allowed. Therefore, it is neither a linear nor a quadratic polynomial. Exam tip: Rewrite a square root as an exponent and check the exponent of the variable.
What is the constant term in the polynomial (14x^2)?
Correct answer: C
A constant term contains no variable; equivalently, it has \(x\) raised to the power 0. The expression \(14x^2\) has only an \(x^2\) term and no term without a variable. Therefore, its constant term is \(0\). Here, \(14\) is the coefficient, not the constant term. Exam tip: identify the term with no variable to find the constant term.
The polynomial \(x^6+x^2+1\) contains only the terms \(x^6\), \(x^2\), and the constant term \(1\); it has no \(x^4\) term. When a term of a particular power is absent, its coefficient is taken as \(0\). Therefore, the correct answer is \(0\). Note that \(1\) is the coefficient of the constant term, not of \(x^4\). Exam tip: First locate the term with the exact power asked in the question.
Yes. Since \(x^0=1\), \(3x^0+5x=3+5x\). The exponents of \(x\) are 0 and 1, both non-negative integers, so it is a polynomial. Option B is incorrect because an exponent of zero is allowed in a polynomial. Exam tip: When you see \(x^0\), simplify it to 1 before deciding whether the expression is a polynomial.
The direct answer is A: yes, it is a polynomial. A polynomial is an expression made from numbers and a variable in which every variable exponent is a non-negative integer: 0, 1, 2, 3, and so on. In this expression, the terms are \\(-\\frac{4}{9}x^4\\), \\(2x\\), and \\(-1\\). Their powers of x are 4, 1, and 0, respectively. The coefficients \\(-\\frac{4}{9}\\), 2, and \\(-1\\) are allowed; coefficients may be negative, fractional, or zero. Therefore the expression satisfies the definition. Option A is correct because all powers are valid and the coefficients are real numbers. Option B is wrong because a negative fraction is still a valid coefficient. Option C is wrong because \\(x^4\\) is perfectly acceptable; 4 is a non-negative integer. Option D is wrong because having three terms does not prevent an expression from being a polynomial; a polynomial may have one, two, three, or many terms. Remember: check the powers of the variable, not whether coefficients are negative or fractional and not merely how many terms appear.
Which expression is not a polynomial because the variable has power \(\frac{5}{6}\)?
Correct answer: B
In a polynomial, every exponent of a variable must be a non-negative integer, such as \(0,1,2,\ldots\). In \(x^{\frac{5}{6}}+4\), the exponent of \(x\) is fractional, so it is not a polynomial. In contrast, \(x^5+6\) has exponent 5 and is a polynomial. Exam tip: while identifying polynomials, check first for negative or fractional exponents of variables.
The degree of a polynomial is the highest power of its variable with a non-zero coefficient. Here, the terms are 8x^2, -9x, and 16, and the highest power of x is 2. Therefore, the degree is 2. The number 8 is a coefficient, not the degree. Exam tip: Look for the highest exponent, not the largest coefficient.
In the polynomial 17x - 5, the power of x in the term 17x is 1 because x = x^1. The constant term -5 has power 0. Since the highest power is 1, its degree is 1. The numbers 5 and 17 are the constant term and coefficient respectively, not the degree. Exam tip: To find the degree, identify the highest exponent of the variable.
What is the degree of the non-zero constant polynomial (-31)?
Correct answer: A
A non-zero constant polynomial has no variable term. It can be written as \(-31x^0\), so the highest power of \(x\) is \(0\); hence its degree is \(0\). A polynomial of degree \(1\) is linear, such as \(x-31\), so it is not correct here. Exam tip: only the zero polynomial has an undefined degree; every non-zero constant has degree \(0\).
What is the correct difference between the zero polynomial and a non-zero constant polynomial?
Correct answer: C
The degree of a polynomial is determined by the greatest exponent whose coefficient is not zero. A non-zero constant, such as 7 or -2, has degree 0 because it can be written as a constant multiplied by \\(x^0\\). The zero polynomial is not the same as an ordinary constant: every coefficient is zero, so there is no greatest exponent with a non-zero coefficient.
Hence the degree of the zero polynomial is not defined, while the degree of a non-zero constant polynomial is 0. This makes option C correct. Option A overlooks the special nature of the zero polynomial. Option B assigns an unsupported degree, and option D is false because the zero polynomial is included among polynomials, even though its degree requires special treatment.
The leading term of a polynomial is the term with the greatest exponent of the variable. In the given polynomial, \(-5x^6\) has exponent 6, which is greater than the exponents of \(3x^4\), \(-x\), and the constant \(9\), namely 4, 1, and 0. Therefore, \(-5x^6\) is the leading term. Exam tip: Compare exponents; whether the coefficient is positive or negative does not determine the leading term.
A student has to identify a polynomial in x. Which of the following expressions is a polynomial in x?
Correct answer: A
In \(4x^3-7x+1\), the powers of x are 3, 1 and 0, all non-negative integers, so it is a polynomial. But \(3/x=3x^{-1}\), which is not allowed. Exam tip: reject expressions with negative or fractional powers.
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