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In this Class 12 Physics topic from Chapter 1, Electric Charges and Fields, students learn how electric flux is related to the net charge enclosed by a closed surface through Gauss’s law. The topic develops the idea of Gaussian surfaces, uses symmetry to simplify electric-field calculations, and applies the law to charged spherical shells, uniformly charged spheres, infinite line charges, and plane sheets. It also helps students understand the electric field inside conductors and choose suitable surfaces for solving electrostatic problems.
TOPIC PRACTICE
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Medium · Level 9View options
Because electric field cannot be treated simply as constant on the chosen surface
Because Gauss's law becomes false
Because closed surface cannot be made
Because charge becomes zero
Medium · Level 9View options
Field magnitude on Gaussian surface being same or simple
Knowing the colour of charge
The surface being real
The surface being open
Medium · Level 9View options
Because surface charge density can be larger there
Because electric field is always zero there
Because charge does not remain on sharp parts
Because field does not form outside conductor
Medium · Level 9View options
Total flux does not change
Total flux always doubles
Total flux becomes zero
Total flux becomes negative
Medium · Level 9View options
Zero
Increases with distance from centre
Maximum outward
Non-zero and independent of distance
Medium · Level 9View options
Zero
Always maximum
Equal to outside field
Only parallel to surface
Medium · Level 9View options
No
Yes, the whole charge
Yes, half charge
It always encloses infinite charge
Medium · Level 9View options
Net enclosed charge is negative
Net enclosed charge is positive
Net enclosed charge is zero
A positive charge must be outside
Medium · Level 9View options
Their distance dependence is different
Field is always zero in all three
Field is independent of distance in all three
Field has same direction in all three
Medium · Level 9View options
It must be a closed surface
It must be metallic
It must be real
It must always be spherical
Medium · Level 9View options
Counting all existing charges instead of enclosed charge
Treating the surface as closed
Identifying symmetry
Writing the unit correctly
Question 1MediumLevel 9
Why does using Gauss's law become difficult for an asymmetric charge distribution?
Correct answer: A
Step 1: Gauss's law remains true for every closed surface. Step 2: But in an asymmetric distribution, field magnitude and direction can be complex on the surface. Step 3: Therefore calculation is not simple.
Which condition is most useful for finding electric field using Gauss's law?
Correct answer: A
Step 1: Gauss's law gives total flux. Step 2: To find field, it is helpful to take field out simply over the surface. Step 3: Therefore symmetry is very useful.
Why can electric field be stronger near sharp parts of a charged conductor?
Correct answer: A
Step 1: Field at a conductor surface is related to surface charge density. Step 2: Sharp regions can have higher surface charge density. Step 3: Hence the electric field can be stronger there.
According to Gauss's law, what happens to total flux if the position of a charge inside a closed surface is changed?
Correct answer: A
Step 1: Total flux depends on net enclosed charge. Step 2: Changing the position of charge inside does not change its value. Step 3: Therefore total flux remains unchanged.
What is the electric field at a point inside a spherical conductor?
Correct answer: A
Step 1: In electrostatic equilibrium, electric field inside any conductor is zero. Step 2: Spherical shape only makes symmetry simpler. Step 3: Hence field inside a spherical conductor is zero.
An empty cavity inside a hollow conductor contains no charge. In electrostatic equilibrium, what is the electric field in the cavity?
Correct answer: A
Step 1: In the conducting material, field is zero in electrostatic equilibrium. Step 2: An empty cavity has no internal charge source. Step 3: Therefore the field inside the cavity is zero.
If a Gaussian surface lies entirely inside the material of a conductor, does it enclose excess surface charge?
Correct answer: A
Step 1: In electrostatic equilibrium, excess charge resides on the conductor surface. Step 2: A surface entirely inside the conducting material does not enclose that surface charge. Step 3: Hence net enclosed charge is zero.
In Gauss's law, outward flux through a closed surface is negative. What conclusion follows about enclosed charge?
Correct answer: A
Step 1: The sign of outward flux is linked to the sign of enclosed charge. Step 2: Negative flux means net field lines are inward. Step 3: Therefore net enclosed charge is negative.
What is the main difference among fields of plane sheet, line charge, and point charge from Gauss's law?
Correct answer: A
Step 1: Point charge field decreases as inverse square of distance. Step 2: Line charge field decreases inversely with distance. Step 3: Infinite sheet field is independent of distance.
Which property of a Gaussian surface is most essential?
Correct answer: A
Step 1: Gauss's law connects total flux with a closed surface. Step 2: A Gaussian surface may be imaginary and can have many shapes. Step 3: But it must be closed.
What is the most common mistake students make in applications of Gauss's law?
Correct answer: A
Step 1: Gauss's law counts only net charge enclosed by the closed surface. Step 2: Charges outside the surface do not change total flux. Step 3: Always check which charges are inside first.
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