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Subjects

Physics

Gauss's Law and its Applications

गाउस का नियम और इसके अनुप्रयोग

In this Class 12 Physics topic from Chapter 1, Electric Charges and Fields, students learn how electric flux is related to the net charge enclosed by a closed surface through Gauss’s law. The topic develops the idea of Gaussian surfaces, uses symmetry to simplify electric-field calculations, and applies the law to charged spherical shells, uniformly charged spheres, infinite line charges, and plane sheets. It also helps students understand the electric field inside conductors and choose suitable surfaces for solving electrostatic problems.

TOPIC PRACTICE

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Up to 25 questions from this page. Select your focus, then start.

25 questions

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Hard · Level 6
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  1. Zero
  2. Positive
  3. Negative
  4. Infinite
Hard · Level 6
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  1. Total flux remains same, but field on the surface is not uniform
  2. Total flux becomes zero
  3. Total flux exists only if charge is at centre
  4. Gauss's law will not apply
Hard · Level 6
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  1. Because field cannot always be taken out simply over the surface
  2. Because Gauss's law is true only for spheres
  3. Because closed surface must be real
  4. Because total flux is always zero
Hard · Level 6
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  1. Because field magnitude and direction are not simple on the surface
  2. Because Gauss's law is wrong in asymmetric cases
  3. Because a closed surface cannot be made
  4. Because asymmetric charges produce no field
Hard · Level 6
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  1. Because electric field is perpendicular to the area vector of the ends
  2. Because the area of the ends is zero
  3. Because line charge produces no field
  4. Because cylinder is not a closed surface
Hard · Level 6
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  1. Because all points on the curved part are at the same distance from the line
  2. Because curved part of cylinder is open
  3. Because field exists only on the ends
  4. Because line charge gives spherical symmetry
Hard · Level 6
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  1. One-third of the earlier value
  2. One-ninth of the earlier value
  3. Three times the earlier value
  4. Unchanged
Hard · Level 6
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  1. Point charge has inverse-square and line charge has simple inverse dependence
  2. Both have inverse-square dependence
  3. Both are independent of distance
  4. Point charge has simple inverse and line charge has inverse-square dependence
Hard · Level 6
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  1. Because electric field is parallel to the side surface
  2. Because side surface has zero area
  3. Because the sheet creates no field
  4. Because the pillbox surface is not closed
Hard · Level 6
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  1. Because field is perpendicular on both sides of the sheet
  2. Because only one face is closed
  3. Because field passes only through side surface
  4. Because field is zero on one side of the sheet
Hard · Level 6
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  1. It remains unchanged
  2. It becomes half
  3. It becomes one-fourth
  4. It becomes double
Hard · Level 6
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  1. It becomes double
  2. It becomes half
  3. It remains unchanged
  4. It becomes one-fourth
Hard · Level 6
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  1. A Gaussian surface inside encloses no charge
  2. Distance inside is infinite
  3. Charge of the shell disappears
  4. Gauss's law does not apply to a spherical shell
Hard · Level 6
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  1. Because an external Gaussian sphere encloses whole charge and spherical symmetry remains
  2. Because there is no charge inside the shell
  3. Because outside field is zero
  4. Because shell is like a plane sheet
Hard · Level 6
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  1. It increases directly with distance
  2. It decreases inversely with square of distance
  3. It remains independent of distance
  4. It remains zero everywhere
Hard · Level 6
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  1. Zero
  2. Maximum
  3. Infinite
  4. Equal to surface value
Hard · Level 6
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  1. Inversely proportional to square of distance
  2. Directly proportional to distance
  3. Independent of distance
  4. Inversely proportional to distance
Hard · Level 6
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  1. At the surface
  2. At the centre
  3. Very far from surface
  4. Same everywhere
Hard · Level 6
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  1. Net enclosed charge inside that surface is zero
  2. A conductor cannot have any charge
  3. Field outside conductor is zero
  4. The surface cannot be imaginary
Hard · Level 6
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  1. Because internal field is zero and an internal Gaussian surface encloses zero net charge
  2. Because conductor volume has no meaning
  3. Because excess charge stays only in air
  4. Because Gauss's law does not apply to conductors
Hard · Level 6
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  1. Otherwise free charges would keep moving on the surface
  2. Because conductors have no free charges
  3. Because surface area is zero
  4. Because Gauss's law treats normal component as wrong
Hard · Level 6
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  1. Surface charge density is larger
  2. Surface charge density is zero
  3. Surface charge density must be negative
  4. It has no relation with surface charge density
Hard · Level 6
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  1. Because surface charge density can be larger at the sharp region
  2. Because charge cannot stay on sharp region
  3. Because field outside a conductor is zero
  4. Because Gauss's law does not apply at sharp region
Hard · Level 6
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  1. Charges of the conductor arrange so that internal field cancels
  2. Outside charges create no field
  3. The cavity is an open surface
  4. Gauss's law applies only outside
Hard · Level 6
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  1. Equal magnitude negative charge
  2. Equal magnitude positive charge
  3. No charge
  4. Infinite charge

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