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In this Class 12 Physics topic from Chapter 1, Electric Charges and Fields, students learn how electric flux is related to the net charge enclosed by a closed surface through Gauss’s law. The topic develops the idea of Gaussian surfaces, uses symmetry to simplify electric-field calculations, and applies the law to charged spherical shells, uniformly charged spheres, infinite line charges, and plane sheets. It also helps students understand the electric field inside conductors and choose suitable surfaces for solving electrostatic problems.
TOPIC PRACTICE
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Up to 25 questions from this page. Select your focus, then start.
25 questions
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Hard · Level 6View options
Zero
Positive
Negative
Infinite
Hard · Level 6View options
Total flux remains same, but field on the surface is not uniform
Total flux becomes zero
Total flux exists only if charge is at centre
Gauss's law will not apply
Hard · Level 6View options
Because field cannot always be taken out simply over the surface
Because Gauss's law is true only for spheres
Because closed surface must be real
Because total flux is always zero
Hard · Level 6View options
Because field magnitude and direction are not simple on the surface
Because Gauss's law is wrong in asymmetric cases
Because a closed surface cannot be made
Because asymmetric charges produce no field
Hard · Level 6View options
Because electric field is perpendicular to the area vector of the ends
Because the area of the ends is zero
Because line charge produces no field
Because cylinder is not a closed surface
Hard · Level 6View options
Because all points on the curved part are at the same distance from the line
Because curved part of cylinder is open
Because field exists only on the ends
Because line charge gives spherical symmetry
Hard · Level 6View options
One-third of the earlier value
One-ninth of the earlier value
Three times the earlier value
Unchanged
Hard · Level 6View options
Point charge has inverse-square and line charge has simple inverse dependence
Both have inverse-square dependence
Both are independent of distance
Point charge has simple inverse and line charge has inverse-square dependence
Hard · Level 6View options
Because electric field is parallel to the side surface
Because side surface has zero area
Because the sheet creates no field
Because the pillbox surface is not closed
Hard · Level 6View options
Because field is perpendicular on both sides of the sheet
Because only one face is closed
Because field passes only through side surface
Because field is zero on one side of the sheet
Hard · Level 6View options
It remains unchanged
It becomes half
It becomes one-fourth
It becomes double
Hard · Level 6View options
It becomes double
It becomes half
It remains unchanged
It becomes one-fourth
Hard · Level 6View options
A Gaussian surface inside encloses no charge
Distance inside is infinite
Charge of the shell disappears
Gauss's law does not apply to a spherical shell
Hard · Level 6View options
Because an external Gaussian sphere encloses whole charge and spherical symmetry remains
Because there is no charge inside the shell
Because outside field is zero
Because shell is like a plane sheet
Hard · Level 6View options
It increases directly with distance
It decreases inversely with square of distance
It remains independent of distance
It remains zero everywhere
Hard · Level 6View options
Zero
Maximum
Infinite
Equal to surface value
Hard · Level 6View options
Inversely proportional to square of distance
Directly proportional to distance
Independent of distance
Inversely proportional to distance
Hard · Level 6View options
At the surface
At the centre
Very far from surface
Same everywhere
Hard · Level 6View options
Net enclosed charge inside that surface is zero
A conductor cannot have any charge
Field outside conductor is zero
The surface cannot be imaginary
Hard · Level 6View options
Because internal field is zero and an internal Gaussian surface encloses zero net charge
Because conductor volume has no meaning
Because excess charge stays only in air
Because Gauss's law does not apply to conductors
Hard · Level 6View options
Otherwise free charges would keep moving on the surface
Because conductors have no free charges
Because surface area is zero
Because Gauss's law treats normal component as wrong
Hard · Level 6View options
Surface charge density is larger
Surface charge density is zero
Surface charge density must be negative
It has no relation with surface charge density
Hard · Level 6View options
Because surface charge density can be larger at the sharp region
Because charge cannot stay on sharp region
Because field outside a conductor is zero
Because Gauss's law does not apply at sharp region
Hard · Level 6View options
Charges of the conductor arrange so that internal field cancels
Outside charges create no field
The cavity is an open surface
Gauss's law applies only outside
Hard · Level 6View options
Equal magnitude negative charge
Equal magnitude positive charge
No charge
Infinite charge
Question 1HardLevel 6
A closed surface encloses four positive and four negative charges of equal magnitude. Field on the surface may be non-zero, but what is the total flux?
Correct answer: A
Step 1: Equal positive and negative charges give zero net enclosed charge. Step 2: Individual charges may create field at the surface. Step 3: But total flux is zero because net enclosed charge is zero.
A point charge is inside a Gaussian sphere but not at the centre. Which statement about total flux is correct?
Correct answer: A
Step 1: Gauss's law relates total flux to enclosed charge, not to central position. Step 2: The charge is still inside, so enclosed charge is same. Step 3: But field on the spherical surface will not be uniform.
Gauss's law is true for every closed surface, yet why is every surface not useful for finding electric field?
Correct answer: A
Step 1: Gauss's law gives total flux. Step 2: To find field, field magnitude and direction must be simple on the chosen surface. Step 3: Therefore a surface matching symmetry is most useful.
Why is it difficult to find electric field using Gauss's law for an asymmetric charge distribution?
Correct answer: A
Step 1: Gauss's law is valid even for asymmetric cases. Step 2: The difficulty is in calculation, not in the law. Step 3: Without symmetry, field cannot be treated as simple on the surface.
For an infinite line charge, why is flux through the flat ends of the cylindrical Gaussian surface zero?
Correct answer: A
Step 1: Field of an infinite line charge is radial. Step 2: Area vectors of flat ends of the cylinder are along the axis. Step 3: Field and area vector are perpendicular, so flux through the ends is zero.
For an infinite line charge, why is field magnitude considered same on the curved part of a cylinder?
Correct answer: A
Step 1: An infinite line charge has cylindrical symmetry. Step 2: All points on the curved surface are at the same distance from the axis. Step 3: Therefore field magnitude is taken same there.
For an infinite line charge, what happens to electric field when distance is made three times?
Correct answer: A
Step 1: Field of an infinite line charge is inversely proportional to distance. Step 2: Tripling distance reduces an inverse relation by three times. Step 3: Hence field becomes one-third.
What is the correct difference in distance dependence between point charge and line charge fields?
Correct answer: A
Step 1: For a point charge, the Gaussian surface is a sphere. Step 2: For a line charge, the Gaussian surface is a cylinder. Step 3: Different area dependence leads to different field-distance relations.
For an infinite plane sheet, why is flux through the side surface of a pillbox Gaussian surface zero?
Correct answer: A
Step 1: Field of an infinite sheet is perpendicular to the sheet. Step 2: On the side surface of the pillbox, the field runs parallel to the surface. Step 3: Since it does not cross that surface, side flux is zero.
For an infinite plane sheet, why is flux taken through both flat faces of the pillbox?
Correct answer: A
Step 1: An infinite uniform sheet has the same symmetry on both sides. Step 2: Field is perpendicular to the sheet on both sides. Step 3: Therefore both flat faces of the pillbox contribute to flux.
For an infinite plane sheet, if distance is doubled while surface charge density remains same, what happens to field?
Correct answer: A
Step 1: Field of an infinite sheet does not depend on distance. Step 2: Its value is related to surface charge density. Step 3: Therefore doubling distance does not change the field.
What happens to the electric field of an infinite plane sheet when surface charge density is doubled?
Correct answer: A
Step 1: Field of an infinite sheet is proportional to surface charge density. Step 2: It changes with charge density, not distance. Step 3: If density doubles, field also doubles.
Inside a charged spherical shell, field at any point is zero. What is the Gauss-law based reason?
Correct answer: A
Step 1: Charge of a spherical shell lies on its surface. Step 2: A Gaussian surface inside the shell encloses no charge. Step 3: With symmetry, Gauss's law gives zero field inside.
Why is the field outside a charged spherical shell treated like a charge at the centre?
Correct answer: A
Step 1: A spherical shell has symmetry about its centre. Step 2: An outside Gaussian sphere encloses the whole charge. Step 3: Hence outside field behaves as if the total charge were at the centre.
Inside a uniformly volume-charged solid sphere, how does electric field change with distance from the centre?
Correct answer: A
Step 1: Inside a uniformly charged solid sphere, a smaller Gaussian surface encloses only the charge within it. Step 2: Enclosed charge grows as cube of radius, while surface area grows as square of radius. Step 3: Hence field inside increases directly with distance from centre.
What is the electric field at the centre of a uniformly volume-charged solid sphere?
Correct answer: A
Step 1: Inside a uniformly charged solid sphere, field is proportional to distance from centre. Step 2: At the centre, distance is zero. Step 3: Therefore electric field at the centre is zero.
Outside a uniformly volume-charged solid sphere, how does electric field depend on distance?
Correct answer: A
Step 1: Outside the sphere, the Gaussian surface encloses the whole charge. Step 2: Due to spherical symmetry, outside field behaves like a point charge at the centre. Step 3: Hence it follows inverse-square dependence.
In a uniformly volume-charged solid sphere, where is the electric field magnitude generally maximum?
Correct answer: A
Step 1: Inside the sphere, field increases with distance from centre. Step 2: Outside the sphere, field decreases with square of distance. Step 3: Therefore maximum value occurs at the surface.
In electrostatic equilibrium, total flux through a Gaussian surface inside a conductor is zero. What conclusion follows?
Correct answer: A
Step 1: Inside a conductor in electrostatic equilibrium, electric field is zero. Step 2: Therefore total flux through an internal Gaussian surface is zero. Step 3: By Gauss's law, net enclosed charge inside it is zero.
Why does excess charge of a conductor not remain in the volume in electrostatic equilibrium?
Correct answer: A
Step 1: Free charges in a conductor arrange so that internal field becomes zero. Step 2: Flux through an internal closed surface is zero. Step 3: Thus excess net charge does not remain in the volume, it resides on the surface.
Why must the tangential component of electric field at a conductor surface be zero?
Correct answer: A
Step 1: Free charges in a conductor can move. Step 2: If a field component exists along the surface, they will not remain at rest. Step 3: Hence in electrostatic equilibrium, field can only be normal to the surface.
The field near the surface of a charged conductor is larger. What does this indicate about surface charge density?
Correct answer: A
Step 1: Field just outside a conductor surface is related to surface charge density. Step 2: Larger field indicates larger local surface charge density. Step 3: This idea is often used for sharp regions of conductors.
Why can electric field be stronger near a sharp conductor?
Correct answer: A
Step 1: Field at a conductor surface is related to surface charge density. Step 2: Charge can be more concentrated near sharp regions. Step 3: Hence the nearby field can be stronger.
A cavity inside a conductor contains no charge. Why does field inside the cavity remain zero even if charges are placed outside?
Correct answer: A
Step 1: In electrostatic equilibrium, field inside conducting material must be zero. Step 2: External influence rearranges charges on the conductor. Step 3: If cavity contains no charge, the field inside it remains zero.
A positive charge is placed inside the cavity of a hollow conductor. What charge is induced on the inner surface to keep field inside the conductor material zero?
Correct answer: A
Step 1: Field inside the conducting material must be zero. Step 2: A positive charge in the cavity tends to create field in the metal. Step 3: Equal negative charge is induced on the inner surface to cancel it in the conductor.
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