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In this Class 12 Physics topic from Chapter 1, Electric Charges and Fields, students learn how electric flux is related to the net charge enclosed by a closed surface through Gauss’s law. The topic develops the idea of Gaussian surfaces, uses symmetry to simplify electric-field calculations, and applies the law to charged spherical shells, uniformly charged spheres, infinite line charges, and plane sheets. It also helps students understand the electric field inside conductors and choose suitable surfaces for solving electrostatic problems.
TOPIC PRACTICE
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Expert · Level 6View options
At the surface
At the centre
At infinite distance
Same everywhere
Expert · Level 6View options
Inversely proportional to square of distance
Directly proportional to distance
Independent of distance
Inversely proportional to distance
Expert · Level 6View options
It becomes half
It becomes one-fourth
It becomes double
It remains unchanged
Expert · Level 6View options
No net excess charge remains in the volume
All excess charge stays in the volume
Only positive charge stays in the volume
Infinite charge stays in the volume
Expert · Level 6View options
Because a tangential component would keep free charges moving along the surface
Because conductors have no free charges
Because surface area is zero
Because outside field is always zero
Expert · Level 6View options
Surface charge density is larger there
Surface charge density is zero there
Field is parallel to the surface there
The conductor has become an insulator there
Expert · Level 6View options
Because surface charge density can be higher at the sharp part
Because charge cannot stay at sharp parts
Because no field exists outside a conductor
Because Gauss's law does not apply near sharp parts
Expert · Level 6View options
Equal magnitude negative charge
Equal magnitude positive charge
Zero
Double positive charge
Expert · Level 6View options
Equal magnitude positive charge
Equal magnitude negative charge
Zero
Double negative charge
Expert · Level 6View options
Zero
Equal to external field
Always maximum
Parallel to surface
Expert · Level 6View options
Positive
Negative
Zero
Depends on outside charge
Expert · Level 6View options
There is net negative charge inside
There is net positive charge inside
Net charge inside is zero
There is no charge outside
Expert · Level 6View options
No, only total flux is zero
Yes, field is zero everywhere
Yes, no charge can exist inside
No, total flux will be positive
Expert · Level 6View options
They are consistent in electrostatics
They contradict each other
Gauss's law is only in magnetism
Coulomb's law is wrong for closed surfaces
Expert · Level 6View options
Three times
One-third
Nine times
Unchanged
Expert · Level 6View options
It remains unchanged
It changes as soon as arrangement changes
It will always be zero
It will depend on surface colour
Expert · Level 6View options
Because total flux is determined by enclosed charge, not area
Because area cannot change
Because Gauss's law applies only to small surfaces
Because field on surface always becomes zero
Expert · Level 6View options
Only by the net charge inside
By all outside negative charges
By all inside and outside charges
By thickness of the surface
Expert · Level 6View options
No, excess charge can stay on the surface
Yes, total charge must be zero
Yes, conductor cannot hold charge
No, field inside is infinite
Expert · Level 6View options
It becomes one-fourth
It becomes half
It becomes double
It remains unchanged
Expert · Level 6View options
Field is zero on every internal sphere
Field is larger on smaller sphere
Field is larger on larger sphere
Field decreases with square of radius
Expert · Level 6View options
Net charge inside the Gaussian surface
Total charge outside the Gaussian surface
Nearest charge
Largest charge
Expert · Level 6View options
Because the surface must be closed to define enclosed charge clearly
Because field cannot exist on open surfaces
Because an open surface is always a conductor
Because flux through open surface is always zero
Expert · Level 6View options
Point charge, infinite line charge, and infinite plane sheet
Infinite line charge, point charge, and dipole
Plane sheet, dipole, and point charge
Dipole, conductor, and line charge
Expert · Level 6View options
First identify closed surface, then enclosed charge, then symmetry
First add all outside charges
First check surface colour
First assume flux is zero
Question 1ExpertLevel 6
Where is the field maximum in a uniformly volume-charged solid sphere?
Correct answer: A
Step 1: Inside the sphere, field increases with distance from centre. Step 2: Outside the sphere, field decreases with square of distance. Step 3: Therefore the maximum occurs at the surface.
Outside a uniformly volume-charged solid sphere, what distance dependence does the field follow?
Correct answer: A
Step 1: Outside the sphere, the Gaussian surface encloses the whole charge. Step 2: By spherical symmetry, outside field behaves like total charge at centre. Step 3: Hence it follows inverse-square dependence.
Inside a uniformly volume-charged solid sphere, how does field change if distance from centre is halved?
Correct answer: A
Step 1: Inside a uniformly charged solid sphere, field is directly proportional to distance from centre. Step 2: Halving distance halves a directly proportional quantity. Step 3: So the inside field becomes half.
Total flux through a Gaussian surface inside a conductor is zero. What does this tell about excess charge in the volume of the conductor?
Correct answer: A
Step 1: Inside a conductor in electrostatic equilibrium, electric field is zero. Step 2: Flux through an internal Gaussian surface is zero. Step 3: Thus no net excess charge remains in the volume; it resides on the surface.
Why is the tangential component of electric field zero at a conductor surface in electrostatic equilibrium?
Correct answer: A
Step 1: Conductors have free charges. Step 2: A field component along the surface would move them. Step 3: In equilibrium charges cannot keep moving, so field is normal to surface.
If electric field is larger at a conductor surface, what local feature is indicated?
Correct answer: A
Step 1: Just outside a conductor, field is related to surface charge density. Step 2: Larger field means larger local surface charge density. Step 3: This explains stronger field near sharp regions.
Why can electric field be very strong near a sharp conductor?
Correct answer: A
Step 1: Field near a conductor surface depends on surface charge density. Step 2: Charge can be more concentrated near sharp parts. Step 3: Hence electric field can be stronger there.
A positive charge is placed in the cavity of an initially neutral hollow conductor. What total charge is induced on the inner surface?
Correct answer: A
Step 1: Field inside conducting material must remain zero. Step 2: The positive charge in cavity tends to create field in the metal. Step 3: Equal negative charge is induced on inner surface to cancel it.
When a positive charge is placed in the cavity of an initially neutral hollow conductor, what total charge appears on the outer surface?
Correct answer: A
Step 1: Equal negative charge is induced on the inner surface. Step 2: The conductor was initially neutral overall. Step 3: To keep total conductor charge zero, equal positive charge appears on outer surface.
External charges are placed outside a conductor with an empty cavity. If there is no charge inside the cavity, what is the field inside the cavity?
Correct answer: A
Step 1: External charges can rearrange charges on the conductor. Step 2: In equilibrium, field inside conducting material remains zero. Step 3: With no internal source in the cavity, field inside the cavity is zero.
More field lines leave a Gaussian surface than enter it. What sign of enclosed charge does this indicate?
Correct answer: A
Step 1: Lines leaving the surface give positive outward flux. Step 2: If leaving is greater, total flux is positive. Step 3: By Gauss's law, net enclosed charge is positive.
More field lines enter a Gaussian surface than leave it. Which conclusion is correct?
Correct answer: A
Step 1: Entering lines contribute negative outward flux. Step 2: If they dominate, total flux is negative. Step 3: By Gauss's law, net enclosed charge is negative.
Field lines entering and leaving a Gaussian surface are equal. Is it necessary that field is zero everywhere on the surface?
Correct answer: A
Step 1: Equal entering and leaving lines make total flux zero. Step 2: Field may still exist on different parts of the surface. Step 3: Do not treat zero total flux as zero local field.
What is the correct statement about Gauss's law and Coulomb's law?
Correct answer: A
Step 1: Both laws deal with electric fields of stationary charges. Step 2: Applying Gauss's law to a point charge gives a Coulomb-law result. Step 3: Treat them as connected, not contradictory.
If enclosed charge becomes three times and permittivity remains the same, how does total flux change?
Correct answer: A
Step 1: In Gauss's law, total flux is proportional to enclosed charge. Step 2: Permittivity is unchanged, so only charge ratio matters. Step 3: Tripling enclosed charge triples the flux.
Inside a closed surface, positive and negative charges are rearranged but net enclosed charge remains the same. What happens to total flux?
Correct answer: A
Step 1: Total flux depends on net enclosed charge. Step 2: Rearrangement may change field distribution on the surface. Step 3: But if net enclosed charge is the same, total flux remains unchanged.
A closed surface area is doubled but the net charge inside remains the same. Why does total flux not change?
Correct answer: A
Step 1: Gauss's law connects total flux with enclosed charge. Step 2: Area change may alter local field or distribution. Step 3: But if net enclosed charge is same, total flux remains unchanged.
A positive charge is inside a closed surface and many negative charges are added outside. What determines total flux?
Correct answer: A
Step 1: In Gauss's law, total flux depends only on enclosed charge. Step 2: Outside charges may change field on the surface. Step 3: But they do not change the net total flux.
Electric field inside a conductor is zero. Is it necessary that total charge on the conductor is also zero?
Correct answer: A
Step 1: In electrostatic equilibrium, field inside a conductor is zero. Step 2: This statement concerns the internal field. Step 3: A conductor may still have excess charge, but it resides on the surface.
Outside a spherical conductor, how does electric field change when distance from centre is doubled?
Correct answer: A
Step 1: Outside a spherical conductor, field behaves as if total charge is at the centre. Step 2: Such field follows inverse-square dependence. Step 3: Doubling distance makes field one-fourth.
Take Gaussian spheres of different radii inside a spherical conductor. Which statement about electric field is correct?
Correct answer: A
Step 1: Inside a conductor in electrostatic equilibrium, electric field is zero. Step 2: Any internal Gaussian surface encloses no net excess charge. Step 3: Therefore field is zero at every interior point.
While applying Gauss's law, which charge should be counted first?
Correct answer: A
Step 1: Gauss's law relates total flux to enclosed charge. Step 2: Outside charges do not change total flux. Step 3: Begin the solution by finding net charge inside.
Why is Gauss's law in enclosed-charge form not applied directly to an open surface?
Correct answer: A
Step 1: Gauss's law connects total flux with a closed surface. Step 2: Only a closed surface completely encloses a volume. Step 3: Hence the enclosed-charge form is not directly used for an open surface.
Spherical, cylindrical, and pillbox Gaussian surfaces are respectively most suitable for which distributions?
Correct answer: A
Step 1: A point charge gives spherical symmetry. Step 2: An infinite line charge gives cylindrical symmetry. Step 3: An infinite sheet gives plane symmetry, so a pillbox is useful.
What is the safest exam method for difficult Gauss's law questions?
Correct answer: A
Step 1: Gauss's law is for closed surfaces, so check whether the surface is closed. Step 2: Then count only net charge inside. Step 3: Finally use symmetry to decide whether field can be found directly.
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