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On A={1,2,3}, let R={(1,2),(2,1),(1,1),(2,2)}. Is R transitive?

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Answer and explanation

Correct answer: Yes

Transitivity concerns only pairs that can be joined through a common middle element. The chain (1,2),(2,1) requires (1,1), which is present; the reverse chain (2,1),(1,2) requires (2,2), also present. Chains involving 1,1 or 2,2 reproduce already listed pairs. Element 3 appears in no pair, so no pair involving 3 is required. Thus R is transitive, making A correct.

Related tags

Transitive RelationSelf PairsRelation Checking

Frequently asked questions

What is the correct answer to this question?

Yes

Why is this the correct answer?

Transitivity concerns only pairs that can be joined through a common middle element. The chain (1,2),(2,1) requires (1,1), which is present; the reverse chain (2,1),(1,2) requires (2,2), also present. Chains involving 1,1 or 2,2 reproduce already listed pairs. Element 3 appears in no pair, so no pair involving 3 is required. Thus R is transitive, making A correct.

Which subject and chapter does this question cover?

This is a Class 12 Mathematics question. Chapter: Relations and Functions. Topic: Transitive relation.

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