When (2.8) radians is approximately converted into degrees, which value is nearest?
\(2.8\times57.3^\circ\approx160.4^\circ\). For estimation take (1) radian as \(57.3^\circ\).
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\(2.8\times57.3^\circ\approx160.4^\circ\). For estimation take (1) radian as \(57.3^\circ\).
View question details(0.75\times57.3^\circ\approx43.0^\circ). The same conversion factor applies for small radian values too.
View question details( \theta=\frac{s}{r}=\frac{14\pi}{21}=\frac{2\pi}{3} ). Use ( \theta=\frac{s}{r} ) to find the angle from arc length.
View question details(s=r\theta=16\times\frac{5\pi}{8}=10\pi) cm. When the angle is in radians, (s=r\theta) applies directly.
View question details(75^\circ=\frac{5\pi}{12}), and (s=24\times\frac{5\pi}{12}=10\pi) cm. Convert degrees to radians before finding the arc.
View question detailsWhen the angle is in radians, the arc-length formula is \(s=r\theta\). Therefore, \(r=\frac{s}{\theta}=\frac{18}{3/4}=18\times\frac{4}{3}=24\) cm. Hence, option C is correct. Option D may result from multiplying \(18\) by \(\frac{3}{4}\), but finding the radius requires division by \(\theta\). Exam tip: In arc-length questions, first check that the angle is expressed in radians.
View question detailsArea is ( \frac{1}{2}r^2\theta=\frac{1}{2}\times196\times\frac{5\pi}{7}=70\pi ). Use this formula directly with a radian angle.
View question details(120^\circ=\frac{2\pi}{3}), and area is ( \frac{1}{2}\times81\times\frac{2\pi}{3}=27\pi ). Convert the degree angle into radians first.
View question detailsFrom (54=\frac{1}{2}\times36\times\theta), ( \theta=3 ) radians. Isolate the unknown angle in the sector area formula.
View question detailsSector area is ( \frac{1}{2}rs ), so (150=\frac{1}{2}\times r\times20) gives (r=15). When arc length is given, ( \frac{1}{2}rs ) is useful.
View question details( \frac{3\pi}{5} ) lies in the second quadrant, and the reference angle is ( \pi-\frac{3\pi}{5}=\frac{2\pi}{5} ). In the second quadrant use ( \pi-\theta ).
View question details( \frac{8\pi}{7} ) lies in the third quadrant, and ( \frac{8\pi}{7}-\pi=\frac{\pi}{7} ). In the third quadrant use ( \theta-\pi ).
View question details( \frac{13\pi}{6}-2\pi=\frac{\pi}{6} ), and it is in the first quadrant. First find the principal angle and then the reference angle.
View question details(300^\circ) lies in the fourth quadrant, and (360^\circ-300^\circ=60^\circ). In the fourth quadrant use (360^\circ-\theta).
View question details(240^\circ) lies in the third quadrant, and (240^\circ-180^\circ=60^\circ). In the third quadrant subtract (180^\circ).
View question details(720^\circ=2\times360^\circ), so its terminal side lies on the positive (x)-axis. Multiples of (360^\circ) return to this axis.
View question details(630^\circ-360^\circ=270^\circ), and (270^\circ) lies on the negative (y)-axis. First find the coterminal angle.
View question details( \frac{15\pi}{2}-6\pi=\frac{3\pi}{2} ), and ( \frac{3\pi}{2} ) lies on the negative (y)-axis. Subtract multiples of (2\pi) to identify the axis.
View question details(1080^\circ=3\times360^\circ), so such angles are coterminal. If the difference is a multiple of (360^\circ), the terminal side is the same.
View question detailsThe angle on the negative (x)-axis is ( \pi ) radians. Axis angles are not placed in quadrants.
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