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On (A={1,2,3,4,5}), (R={(a,b):a+b=6}). Which counterexample correctly tests transitivity?

Answer and explanation

Correct answer: ((2,4)) and ((4,2)) are present but ((2,2)) is absent

Step 1: (2+4=6), so ((2,4)) is in the relation, and (4+2=6), so ((4,2)) is also in the relation. Step 2: Transitivity requires ((2,2)), but (2+2=4), so it is not in the relation. Step 3: In a counterexample, the middle element must match.

Related tags

Constant Sum RelationCounterexampleNon TransitiveClass 12Transitive RelationRelations And FunctionsMathematicsClass 12 Mcq

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