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On integers, (aRb) is defined when (a \equiv b \pmod{5}). Is this relation transitive?

Answer and explanation

Correct answer: Yes, it is transitive

Step 1: (a \equiv b \pmod{5}) means (a-b) is divisible by (5). Step 2: If (b-c) is also divisible by (5), then (a-c=(a-b)+(b-c)) is divisible by (5). Step 3: For congruence relations, remember the sum of differences.

Related tags

Congruence ModuloTransitive RelationIntegersClass 12Relations And FunctionsMathematicsClass 12 Mcq

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