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On real numbers, (aRb) if (a\le b+2). Is this relation transitive?

Answer and explanation

Correct answer: No, the example (a=5,b=3,c=1) breaks the condition

Step 1: Check that (5\le3+2) and (3\le1+2) are both true. Step 2: But (5\le1+2) is false, so ((5,1)) is not in the relation. Step 3: For modified inequalities, do not decide only by seeing (\le); look for a counterexample.

Related tags

Modified InequalityCounterexampleNon TransitiveTransitive RelationRelations And FunctionsMathematicsClass 12 Mcq

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