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On the integers, define aRb when a+b is even. Is R transitive?

Answer and explanation

Correct answer: Yes, because parity is preserved

The condition aRb means that a and b have the same parity: both are even or both are odd. If aRb and bRc, then a and b have the same parity, and b and c also have the same parity. Consequently, a and c have the same parity, so a+c is even and aRc. The argument works for all integers, including negative values, so A is correct.

Related tags

Parity RelationIntegersTransitivity

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