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On real numbers, (aRb) if (a\le 2b). Is this relation transitive?

Answer and explanation

Correct answer: No

Step 1: From (a\le 2b) and (b\le 2c), we only get (a\le 4c). Step 2: Transitivity requires (a\le 2c), which need not hold. Take (a=4), (b=2), (c=1); (4\le4), (2\le2), but (4\le2) is false. Step 3: In multiplier-based relations, the bound may change.

Related tags

Algebraic InequalityNon TransitiveCounterexampleTransitive RelationRelations And FunctionsMathematicsClass 12 Mcq

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