On which interval is \(\sin^{-1}x\) increasing?
The function \(\sin^{-1}x\) is increasing on its domain \(\left[-1,1\right]\). In graph questions, check both domain and trend.
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SubjectsMathematics
प्रतिलोम त्रिकोणमितीय फलनों के ग्राफ
In this Class 12 Mathematics topic from the chapter “Inverse Trigonometric Functions,” students learn how to sketch and interpret the graphs of sin⁻¹x, cos⁻¹x, tan⁻¹x and related functions. The topic connects each graph with its parent trigonometric function through reflection and restriction of domain, while emphasizing principal values, domains, ranges, intercepts, symmetry and key points. Students also examine how transformations affect these graphs and use them to understand inverse-function relationships.
TOPIC PRACTICE
Up to 4 questions from this page. Select your focus, then start.
The function \(\sin^{-1}x\) is increasing on its domain \(\left[-1,1\right]\). In graph questions, check both domain and trend.
View question detailsSince \(sin^{-1}0=0\), the graph passes through \(\left(0,0\right)\). Basic values are useful in graph questions.
View question detailsSince \(\cos^{-1}1=0\), the graph passes through \(\left(1,0\right)\). Remember standard values for graph questions.
View question detailsThe governing concept is the odd-function property of the principal branch of inverse sine. For every x in the domain [-1, 1], arcsin(-x) = -arcsin(x). This follows because sine is odd and the principal range of arcsin is [-π/2, π/2], which is symmetric about zero. Thus changing the input from x to −x changes the output sign only, so option A is correct. Option B incorrectly treats arcsin as an even function. Option C is a relation associated with arccos, not arcsin, while option D is not the correct negative-input identity. The domain restriction is essential because real arcsin values exist only when the input lies between −1 and 1.
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