Population Density

Very high average density means that many people live in a limited amount of land. Planning authorities must provide enough homes, roads, public transport, drinking water, drainage, electricity, schools, hospitals and waste-management services for this large concentration of people. If supply does not keep pace with demand, overcrowding, congestion and pressure on basic services may develop.

Therefore, option A is correct because housing and infrastructure are directly affected by population concentration. Ocean-depth measurement, mountain-height surveys and longitude calculations may be useful for particular scientific or mapping tasks, but they are not the main planning pressure created by high population density.

National average density uses the whole country: total population divided by total land area. The entire desert is included in the area even if almost nobody lives there. At the same time, a few cities may contain many people in very small spaces. Combining these very different places into one calculation produces a single average, not a detailed picture of settlement patterns.

Therefore, option B is correct: the national average can hide local extremes. It may appear moderate even when cities are extremely crowded and the desert is nearly empty. It does not show only city density, and it does not ignore the desert; both contribute to the national calculation. Option A is wrong because an average cannot fully display internal variation.

A 10 percent population decrease leaves 90 percent of the original population. The new population is therefore \(160{,}000\times0.90=144{,}000\). The area does not change, so it remains 400 square kilometres. New density is calculated as \(\frac{144{,}000}{400}=360\) persons per square kilometre.

Thus option C is correct. Another quick way is to note that density also falls by 10 percent when area stays fixed: \(400\times0.90=360\). Option A is not the result of a 10 percent reduction, and B and D represent smaller or different changes. The original density of 400 is reduced because the same land area now supports fewer people. The supplied answer and calculation are accurate.

Arithmetic population density measures the average number of people living in each unit of total area. It is useful as an initial indicator because a high concentration of people may place greater demand on housing land, roads, water, sanitation, schools, and other services. It can therefore suggest pressure on available space and resources, although it does not measure the actual quantity or quality of every resource.

Option A is correct because it states exactly what density indicates: people per unit area. Option B is wrong because density does not directly tell us how much water, land, or fuel exists. Options C and D are unrelated consequences and use absolute language. Density should be interpreted with resource availability, technology, income, and local conditions rather than treated as a complete measure of carrying capacity.

Population density measures the average number of people living in one unit of area. The formula is \(Population\ density = \frac{Population}{Area}\). Here the population is 216,000 and the area is 900 square kilometres. Dividing gives \(216000 \div 900 = 240\), so the average density is 240 persons per square kilometre.

Option C is correct because it has the result with the required unit. The calculation can also be checked by noting that 900 multiplied by 240 equals 216,000. Option A is too low, while B and D do not result from the stated division. This is an average for the whole region; it does not mean that every square kilometre contains exactly 240 people. Therefore C is the correct choice.

When density and area are known, total population is obtained by multiplying them: \(P=D\times A\). In this case, \(D=180\) persons per square kilometre and \(A=750\) square kilometres. Thus, \(P=180\times750=135000\) persons. The square-kilometre unit in density cancels with the square-kilometre area, leaving people as the final unit.

Option B is correct. A quick calculation is \(180\times(75\times10)=13,500\times10=135,000\). Dividing density by area would be the wrong operation and would not produce a population value. Option A is 15,000 too low, option C is 15,000 too high, and option D is 45,000 too high. The multiplication formula directly determines the answer.

The relationship among population, density, and area is \(Population=Density\times Area\). Rearranging it gives \(Area=\frac{Population}{Density}\). Substituting the values, \(Area=\frac{144000}{160}\). Since \(160\times900=144000\), the area is 900 square kilometres.

Therefore option C is correct. The units also support the calculation: persons divided by persons per square kilometre leaves square kilometres. Multiplying density by population would be incorrect because that would not produce an area. The values 720, 800, and 960 do not satisfy the original relationship; for example, an area of 800 would give only 128,000 people at density 160. Hence the supplied answer is clear and consistent.

The correct answer is A, Region A. Density equals population divided by area. With equal populations, the region with the smaller area has the higher density. Region A has 75% of Region B’s area, so its density is the same population divided by a smaller area. In fact, it is 1 ÷ 0.75, or about 1.33 times, Region B’s density.

Density is population divided by area. If two regions have exactly the same area, their population sizes change in the same proportion as their densities. Thus, comparing their densities is enough to compare their populations; the common area does not distort the comparison.

Let Region Y have population \(P\) and area \(A\). Its density is \(P/A\). If Region X has density 40% more, its density is \(1.4(P/A)\). Since X also has area \(A\), its population is \(1.4P\), or 40% more than Y's. It is not twice as large. Therefore, option A is correct.

Population density is a ratio, so its change depends on both population and area. If the original population is \(P\) and area is \(A\), the original density is \(P/A\). A 30% population increase makes population \(1.3P\), while a 10% area increase makes area \(1.1A\). Thus the new density is \(\frac{1.3P}{1.1A}=1.1818\frac{P}{A}\).

The new density is therefore about 118.18% of the old density. The increase is \(118.18-100=18.18\%\), approximately 18.2%. Hence option B is correct. Simply subtracting 10% from 30% would give 20%, but that shortcut ignores that the changed area is in the denominator and does not give the exact ratio.

Density is the ratio of population to area. If both population and area are reduced by the same percentage, their ratio does not change. A 15 percent decrease leaves 85 percent of each original value. Thus the new density is \(0.85P/0.85A\), and the common factor 0.85 cancels. The relationship between people and space remains exactly the same.

For instance, suppose population is 850 and area is 100 square kilometres. The density is 8.5. After a 15 percent decrease, population is 722.5 and area is 85 square kilometres. The new density is \(722.5/85=8.5\). Therefore, option C, density remains unchanged, is correct. It would decrease only if population fell proportionally more than area.

Population density is calculated as population divided by area. If the original population is \(P\) and area is \(A\), the original density is \(P\div A\). A 40% population increase makes the population \(1.4P\), while a 20% area decrease makes the area \(0.8A\). The new density is therefore \(1.4P\div0.8A = 1.75(P\div A)\).

Thus, the new density is 1.75 times the original density. Both changes raise density: there are more people and less area. Option C is correct. It is not enough to add 40% and 20% as ordinary percentage changes; the area change affects the denominator, so division by 0.8 is essential. This produces 1.75, not 1.4, 1.5, or 2 times.

Density equals population divided by area. A decrease of 25 percent leaves 75 percent of the original population, while an increase of 25 percent makes the area 125 percent of its original value. The new density must therefore account for both changes rather than considering only the population change.

Let the original density be \(P/A\). The new density is \(0.75P\div1.25A=(0.75/1.25)(P/A)=0.6(P/A)\). Thus, the new density is 60 percent of the original density, so option A is correct. Simply adding or subtracting the two percentages would be wrong because the population and area affect density through division, not by direct addition.

Correct answer: B, 300,000 people. The relationship among population, density, and area is density = population ÷ area. Rearranging gives population = density × area. Therefore, population = 480 × 625 = 300,000. One convenient method is 625 × 48 = 30,000, followed by multiplying by 10 to obtain 625 × 480 = 300,000. Option A is too small; 480 × 625 is not 250,000. Option C would result from an incorrect multiplication. Option D is also greater than the correct product. A reverse check confirms the answer: 300,000 ÷ 625 = 480 persons per square kilometre. The final answer is a total number of people, so it should not be expressed in persons per square kilometre; that unit belongs to density.

Population density tells us how many people live, on average, in one square kilometre. It is found by dividing the total population by the total area. The unit is persons per square kilometre, so both the population and the area must be used in the stated units. This measure allows regions of different sizes to be compared fairly.

Here, density is \(198000 \div 660\). Since \(660 \times 300=198000\), the quotient is 300 persons per square kilometre. Therefore, option C is correct. A value such as 330 would result from an incorrect division and does not reproduce the given population when multiplied by 660.

Population density is the number of people living per unit of area. When population and density are known, area is found by dividing the total population by the population in each square kilometre. This is the inverse of the formula \(Population=Density\times Area\), so the units also confirm the method.

Substitute the values: \(Area=270000\div225\). Since \(225\times1200=270000\), the area is 1200 square kilometres. Thus option B is correct. Dividing by 225 rather than multiplying is essential; multiplication would produce a quantity much larger than the stated population and would not have the correct area interpretation.

Population density changes when the number of people changes, while the area remains the same. First find the population left after migration. From 320,000 people, 80,000 leave, so the remaining population is \(320000-80000=240000\). The area is still 1,600 square kilometres because no change in area is mentioned.

Now apply the density formula: \(\text{density}=\text{population}/\text{area}=240000/1600\). Dividing both numbers gives 150 persons per square kilometre. Therefore, option B is correct. The original density was 200 persons per square kilometre, and the decrease to 150 is reasonable because out-migration reduces population without reducing the area.

Population density is found by dividing the number of people by the area they occupy. When people migrate into a region, its population increases. If the area does not change, the new density must also rise because more people are living in the same space.

The new population is \(180000+45000=225000\). The area remains 900 square kilometres, so the new density is \(225000\div900=250\) persons per square kilometre. Thus option C is correct. The value 200 is the original density, while 225 would not be obtained by simply adding the number of migrants to the old density.

Population density tells us how many people live in one unit of area. It is calculated by dividing the total population by the total area. When the population stays fixed but the area becomes larger, the same people are spread over more land, so the density becomes lower. The correct choice is B, 480 persons per square kilometre.

Use the formula \(\text{density}=\frac{\text{population}}{\text{area}}\). Thus, \(\frac{240000}{500}=480\) persons per square kilometre. The earlier density was \(\frac{240000}{400}=600\), so the increase in area reduced the density from 600 to 480. Choice A uses the wrong division, while choice D is the old density, not the new one.

When population stays constant, density changes inversely with area. An area increase of 20 percent means the new area is \(1.20A\), not just \(0.20A\). Therefore, the new density is \(P/(1.20A)\), which equals the old density divided by 1.2. More area is now available for the same number of people, so the density must fall.

Using the given value, the calculation is \(360/1.2=300\) persons per square kilometre. Equivalently, if the original area were 100 units, the new area would be 120 units and the same population would be distributed across those 120 units. Hence option B is correct. The value 432 would result from multiplying by 1.2, which is inappropriate when population is fixed.

When area remains unchanged, density changes in the same proportion as population because density is population divided by area. A 20 percent population increase therefore produces a 20 percent density increase. Starting with 250 persons per square kilometre, calculate \(250\times1.20=300\). Thus, the correct choice is B.

The additional density is 20 percent of 250, which is \(250\times0.20=50\). Adding this to the original density gives \(250+50=300\). The unchanged area is important: if area had also changed, the result would require comparing both percentage changes. Here the denominator stays fixed, so the population increase passes directly to the density. The other choices do not represent a 20 percent rise from 250.

Direct answer: Option B, 25 percent. Population density falls from 480 to 360, so the absolute decrease is 480 − 360 = 120 persons per square kilometre. For a percentage decrease, always compare the decrease with the original value, not the final value. Therefore, percentage decrease = (120 ÷ 480) × 100 = 25%. Option A is incorrect because 20% does not result from this calculation. Option B is correct because it matches the exact result. Option C is incorrect because 30% would mean a decrease of 144 from the original 480. Option D is incorrect because 33.3% is obtained by an unsuitable comparison with the new value or by rough estimation. Memory cue: percentage decrease uses original value as the denominator.

Direct answer: Option C, 40 percent. First find the absolute increase: 210 − 150 = 60 persons per square kilometre. Percentage increase is calculated relative to the original density, so use 150 as the denominator: (60 ÷ 150) × 100 = 40%. Option A is wrong because 30% would give an increase of only 45 over 150. Option B is wrong because 35% would give 52.5, not 60. Option C is correct because 60 is 40% of 150. Option D is wrong because 60 is the absolute increase, not the percentage increase. Common confusion: the number 60 must not be written as 60% unless the base value is exactly 100.

Density is calculated as population divided by area, \(D=P/A\). If density must remain unchanged, population and area must increase in the same proportion. Therefore, a population increase alone would raise density, so the area must also expand to accommodate the additional people at the original density.

Suppose the original population and area are P and A. After a 10 percent increase, the population is \(1.1P\). Keeping density equal gives \(1.1P/A' = P/A\), so \(A'=1.1A\). The area therefore increases by 10 percent. Hence option A is correct; it does not remain unchanged because the population has changed.

Population density is population divided by area, so when population stays fixed, density and area change in opposite directions. A higher density means the same number of people are being counted within a smaller area. The area therefore cannot increase or remain unchanged when density rises.

Let the original density and area be \(D\) and \(A\). A 25 percent rise makes density \(1.25D\). Since population is constant, \(P=DA=(1.25D)A_{new}\). Thus \(A_{new}=A/1.25=0.8A\). The new area is 80 percent of the old area, so it decreases by 20 percent. Therefore, option B is correct.